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r - 使用 ftransform 和来自折叠 R 包的 fgroup_by

转载 作者:行者123 更新时间:2023-12-04 12:29:25 25 4
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我正在尝试重现 dplyr 的以下输出代码与 R包裹collapse .
dplyr代码

library(tidyverse)
starwars %>%
select(name, mass, species) %>%
group_by(species) %>%
mutate(mass_norm = mean(mass, na.rm = TRUE))
dplyr代码输出
# A tibble: 87 x 4
# Groups: species [38]
name mass species mass_norm
<chr> <dbl> <chr> <dbl>
1 Luke Skywalker 77 Human 82.8
2 C-3PO 75 Droid 69.8
3 R2-D2 32 Droid 69.8
4 Darth Vader 136 Human 82.8
5 Leia Organa 49 Human 82.8
6 Owen Lars 120 Human 82.8
7 Beru Whitesun lars 75 Human 82.8
8 R5-D4 32 Droid 69.8
9 Biggs Darklighter 84 Human 82.8
10 Obi-Wan Kenobi 77 Human 82.8
# … with 77 more rows
collapse代码
library(collapse)
starwars %>%
fselect(name, mass, species) %>%
fgroup_by(species) %>%
ftransform(mass_norm = fmean(mass, na.rm = TRUE))
collapse代码输出
# A tibble: 87 x 4
name mass species mass_norm
* <chr> <dbl> <chr> <dbl>
1 Luke Skywalker 77 Human 97.3
2 C-3PO 75 Droid 97.3
3 R2-D2 32 Droid 97.3
4 Darth Vader 136 Human 97.3
5 Leia Organa 49 Human 97.3
6 Owen Lars 120 Human 97.3
7 Beru Whitesun lars 75 Human 97.3
8 R5-D4 32 Droid 97.3
9 Biggs Darklighter 84 Human 97.3
10 Obi-Wan Kenobi 77 Human 97.3
# … with 77 more rows

Grouped by: species [38 | 2 (5.5)]
想知道为什么我的答案是错误的 collapse代码。任何提示。

最佳答案

fmean默认使用 na.rm = TRUE .此外,还有一个选项可以指定 fmean 内的分组。即 g .默认情况下,TRANULL它返回一个汇总输出,但我们可以将其更改为 replace_fill返回全长

library(collapse)
ftransform(slt(starwars, name, mass, species),
mass_norm = fmean(mass, species, TRA = 'replace_fill'))
-输出
# A tibble: 87 x 4
# name mass species mass_norm
# * <chr> <dbl> <chr> <dbl>
# 1 Luke Skywalker 77 Human 82.8
# 2 C-3PO 75 Droid 69.8
# 3 R2-D2 32 Droid 69.8
# 4 Darth Vader 136 Human 82.8
# 5 Leia Organa 49 Human 82.8
# 6 Owen Lars 120 Human 82.8
# 7 Beru Whitesun lars 75 Human 82.8
# 8 R5-D4 32 Droid 69.8
# 9 Biggs Darklighter 84 Human 82.8
#10 Obi-Wan Kenobi 77 Human 82.8
# … with 77 more rows
如果我们要使用链,使用 GRP指定 g或数据上的分组变量( . )
library(dplyr)
starwars %>%
fselect(name, mass, species) %>%
fgroup_by(species) %>%
ftransform(mass_norm = fmean(mass, GRP(.), TRA = 'replace'))

关于r - 使用 ftransform 和来自折叠 R 包的 fgroup_by,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/67349744/

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