c - 为什么当我们输入 8 和 11 时结果 "eightnine"在一起？

Question

当我用输入 8 和 11 运行我的代码时，输​​出是

eightnine
odd
even
odd

我期望的结果是:

eight
nine
odd
even

为什么 eightnine 出现在同一行？循环有问题吗？

#include <stdio.h>
#include <string.h>

int main() {
int a, b;

    scanf("%d\n%d", &a, &b);

    char list[11][5]={"one","two","three","four","five","six","seven","eight","nine","even","odd"};
    int i;
    for (i=a;i<=b;i++)
    {
        printf("%s \n",(i<9?list[i-1]:list[9+i%2]));
    }

     return 0;
}

Answer 1

您需要 char list[11][6]，即您需要为 5 个字符的单词的 NUL(终止 C 风格字符串的 0)留出空间。

尽管如此，我更愿意

char* list[] ={"one","two","three","four","five","six","seven","eight","nine","even","odd"};

所有这些问题都会消失。让编译器进行计数!