r - lm.fit(x, y, offset = offset, single.ok = single.ok, ...) : NA/NaN/Inf in 'y' , 中的错误尝试了所有可能的方法

Question

这里我的数据集是 pd我已将其拆分为训练和测试数据 pd_train1和 pd_train2

    sku national_inv lead_time in_transit_qty forecast_3_month forecast_6_month
1 3921548            8        12              0                0                0
2 3191009           83         2             33              157              377
3 2935810            8         4              0                0                0
4 2205847           31         4             63               70              160
5 4953497            3        12              0                0                0
6 2286884            0         8              0                0                0
  forecast_9_month sales_1_month sales_3_month sales_6_month sales_9_month min_bank
1                0             1             1             2             5        2
2              603            44            98           148           156       53
3                0             0             0             1             1        0
4              223            27            90           164           219        0
5                0             0             0             0             0        0
6                0             0             0             0             0        0
  potential_issue pieces_past_due perf_6_month_avg perf_12_month_avg local_bo_qty
1               0               0             0.63              0.75            0
2               0               0             0.68              0.66            0
3               0               0             0.73              0.78            0
4               0               0             0.73              0.78            0
5               0               0             0.81              0.74            0
6               0               0             0.91              0.96            0
  deck_risk oe_constraint ppap_risk stop_auto_buy rev_stop went_on_backorder  data
1         0             0         0             1        0                No train
2         0             0         0             1        0                No train
3         0             0         0             1        0                No train
4         0             0         1             1        0                No train
5         0             0         0             1        0                No train
6         0             0         0             1        0                No train

我想为我的训练数据创建一个 lm 模型 pd_train1但我收到此错误如下:

> fit=lm(went_on_backorder~.,data=pd_train1)
Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) : 
  NA/NaN/Inf in 'y'
In addition: Warning message:
In storage.mode(v) <- "double" : NAs introduced by coercion

我尝试搜索无限值:

sapply(pd_train1, function(x) sum(is.infinite(x)))
             sku      national_inv         lead_time    in_transit_qty  forecast_3_month 
                0                 0                 0                 0                 0 
 forecast_6_month  forecast_9_month     sales_1_month     sales_3_month     sales_6_month 
                0                 0                 0                 0                 0 
    sales_9_month          min_bank   potential_issue   pieces_past_due  perf_6_month_avg 
                0                 0                 0                 0                 0 
perf_12_month_avg      local_bo_qty         deck_risk     oe_constraint         ppap_risk 
                0                 0                 0                 0                 0 
    stop_auto_buy          rev_stop went_on_backorder              data 
                0                 0                 0                 0 

以及我想要制作线性模型的训练数据中的 NA/NaN 值

     sku      national_inv         lead_time    in_transit_qty  forecast_3_month 
                0                 0                 0                 0                 0 
 forecast_6_month  forecast_9_month     sales_1_month     sales_3_month     sales_6_month 
                0                 0                 0                 0                 0 
    sales_9_month          min_bank   potential_issue   pieces_past_due  perf_6_month_avg 
                0                 0                 0                 0                 0 
perf_12_month_avg      local_bo_qty         deck_risk     oe_constraint         ppap_risk 
                0                 0                 0                 0                 0 
    stop_auto_buy          rev_stop went_on_backorder 
                0                 0                 0 


Inf %in% pd_train1$went_on_backorder
1] FALSE

NaN %in% pd_test$went_on_backorder
1] FALSE

此后我无法在我的数据集中获得 NA/NaN/Inf 值
有人可以帮我理解为什么会抛出错误吗？
这里 went_on_backorder是我的目标变量。

Answer 1

栏目went_on_backorder是一个因素。线性回归需要一个数字响应变量。

要使用逻辑回归，请使用 glm在基础 R 或诸如 vgam 之类的包中.下面是一个简短的例子:

pd_train1 <- data.frame('went_on_backorder' = c('No','Yes','Yes'), 'lead_time' = 1:3)
model <- glm(went_on_backorder ~ ., data = pd_train1, family = 'binomial')

你可以预测你的类(class):

predict(model, newdata = data.frame('lead_time' = c(0,1,2.5,3.5)), type = "response")