Graphviz:边缘与具有neato的传递节点之间的距离

Question

布局引擎是 neato 。我想在从a到c的箭头与节点b之间有更多的空间。 margin和pad对neato没有帮助。这是我的图:

digraph G {
  splines=true      

  a [pos="0.0,0.0!"];
  b [pos="0.0,1.0!"];
  c [pos="0.0,2.0!"];  

  a -> b;
  a -> c;
  b -> c;
}

那可能吗？

Answer 1

采用原始图形定义，添加esep=1属性以获得以下内容:

digraph G {
  splines=true; esep=1;


  a [pos="0.0,0.0!"];
  b [pos="0.0,1.0!"];
  c [pos="0.0,2.0!"];  

  a -> b;
  a -> c;
  b -> c;
}

将使用 neato 输出以下内容:

按照该属性的 documentation:

Margin used around polygons for purposes of spline edge routing. The interpretation is the same as given for sep. This should normally be strictly less than sep.