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php - UrlGenerationException(缺少 [Route] 所需的参数)

转载 作者:行者123 更新时间:2023-12-04 12:20:04 24 4
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我不知道这个错误是从哪里来的。尝试更新记录时出现此错误。它可以正常工作并更新到我的数据库中,但出现此错误。它说那错过了我的参数中的某些内容。我认为我的错误是 return redirect()->route('account.show');当我试图重定向到我的 显示 更新后查看。但是当我重定向到其他工作正常时。有什么意见吗?

Missing required parameters for [Route: account.show] [URI: show/{id}].



我有 3 个 Blade 模板。 搜索 , 编辑 显示 .

search.blade.php - 显示所有记录。
@foreach ($result as $row)
<tr class = "success">
<td>{{ $row->id }}</td>
<td>{{ $row->first_name }}</td>
<td>{{ $row->last_name }}</td>
<td>{{ $row->middle_name }}</td>
<td>{{ $row->email }}</td>
<td>{{ $row->username }}</td>
<td>
<a href = "{{ route ('account.show', $row->id) }}"><button type = "submit" class = "btn btn-info">View</button></a>

<a href = "{{ route ('account.edit', $row->id) }}"><button type = "submit" class = "btn btn-warning">Edit</button></a>

<a href = "{{ route ('result.destroyEmployee', $row->id) }}"><button type = "submit" class = "btn btn-danger">Archive</button></a>
</td>
</tr>
@endforeach

edit.blade.php - 点击提交按钮后出现错误的地方是 保存
<div class = "col-md-6">
<form class = "form-vertical" role = "form" method = "post" action = "{{ route ('account.edit', $result->id) }}">

<h3>Edit Employee</h3>
<hr>

<div class = "form-group">

<label for = "email" class = "control-label">Email Address</label>
<input type = "text" name = "email" class = "form-control" value = "{{ $result->email }}">

</div>

<div class = "form-group">

<label for = "username" class = "control-label">Username</label>
<input type = "text" name = "username" class = "form-control" value = "{{ $result->username }}">

</div>

<div class = "form-group">

<button type = "submit" class = "btn btn-success">Save</button>

</div>

<input type = "hidden" name = "_token" value = "{{ Session::token() }}">

</form>

show.blade.php - 文本字段只会放置记录的值。
<div class = "col-md-6">
<form class = "form-vertical" role = "form" method = "post" action = "{{ route ('account.show', $result->id) }}">

<h3>View Employee</h3>
<hr>

<div class = "form-group">

<label for = "email" class = "control-label">Email Address</label>
<input type = "text" name = "email" class = "form-control" placeholder = "{{ $result->email }}" readonly>

</div>

<div class = "form-group">

<label for = "username" class = "control-label">Username</label>
<input type = "text" name = "username" class = "form-control" placeholder = "{{ $result->username }}" readonly>

</div>

<input type = "hidden" name = "_token" value = "{{ Session::token() }}">

</form>

路线:
//READ
Route::get('/search',
[
'uses' => '\App\Http\Controllers\AccountController@getEmployee',
'as' => 'account.search',
]);


//SHOW
Route::get('/show/{id}',
[
'uses' => 'AccountController@showEmployee',
'as' => 'account.show',
]);

//EDIT
Route::get('/edit/{id}',
[
'uses' => '\App\Http\Controllers\AccountController@editEmployee',
'as' => 'account.edit',
]);


//UPDATE
Route::post('/edit/{id}',
[
'uses' => '\App\Http\Controllers\AccountController@updateEmployee',
'as' => 'account.edit',
]);

最佳答案

尝试改变这一点:

<form class = "form-vertical" role = "form" method = "post" action = "{{ route ('account.show', $result->id) }}">

至:
 <form class = "form-vertical" role = "form" action="{{ url('edit/'. $result->id) }}" method="POST">

然后你必须将路由参数作为第二个参数传递给路由。像这样: return redirect()->route('account.show', [$id])
*我建议你使用 laravel 集体形式: https://laravelcollective.com/

使用 laravel 集体,您可以执行以下操作:
{!! Form::open(array('route' => array('account.show', $result->id))) !!}

关于php - UrlGenerationException(缺少 [Route] 所需的参数),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38177872/

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