r - 如何从 2 个向量中创建一个对列表

Question

这个问题在这里已经有了答案:

Make list of vectors by joining pair-corresponding elements of 2 vectors efficiently in R (1 个回答)

关闭 8 年前。

说我有

X = seq(1,10,1)
X0 = c(-Inf,X)
X1 = c(X,Inf)

如何列出对(-Inf,1);(1,2);...;(10,+Inf)

这很接近但并不完全

R) test = mapply(c,c(-Inf,thresh),c(thresh,Inf))
R) test
     [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14] [,15] [,16] [,17] [,18] [,19] [,20]
[1,] -Inf    5   10   15   20   25   30   35   40    45    50    55    60    65    70    75    80    85    90    95
[2,]    5   10   15   20   25   30   35   40   45    50    55    60    65    70    75    80    85    90    95   Inf

Answer 1

你快到了:

mapply(c, X0, X1, SIMPLIFY = FALSE)
# [[1]]
# [1] -Inf    1
#
# [[2]]
# [1] 1 2
# ...
# [[11]]
# [1]  10 Inf