django - 无法使用 View 名称 (django-rest-framework) 解析超链接关系的 URL

Question

问题 :

我收到这样的错误。

ImproperlyConfigured at /api/users/

Could not resolve URL for hyperlinked relationship using view name "user-detail". You may have failed to include the related model in your API, or incorrectly configured the lookup_field attribute on this field.

我读了这个 post但它没有用。

序列化程序.py

class UserSerializer(serializers.ModelSerializer):
    url = serializers.HyperlinkedIdentityField(view_name='user-detail',
                                               lookup_field='profile')

    class Meta:
        model = User
        fields = ('id', 'username', 'first_name', 'last_name', 'url')


class UserProfileSerializer(serializers.ModelSerializer):
    user = serializers.ReadOnlyField(source='user.username')

    class Meta:
        model = UserProfile
        fields = "__all__"
        # user = serializers.ReadOnlyField(source='owner.username')

    def create(self, validated_data):
        pass

    def update(self, instance, validated_data):
        pass

网址.py

user_profile_list = UserProfileViewSet.as_view({
    'get': 'list',
    'post': 'create'
})
user_profile_detail = UserProfileViewSet.as_view({
    'get': 'retrieve',
    'put': 'update',
    'patch': 'partial_update',
    'delete': 'destroy'
})
user_list = UserViewSet.as_view({
    'get': 'list'
})
user_detail = UserViewSet.as_view({
    'get': 'retrieve'
})
user_profiles_detail = UserViewSet.as_view({
    'get': 'profile'
})

router = DefaultRouter()
router.register(r'userprofiles', views.UserProfileViewSet)
router.register(r'users', views.UserViewSet)

urlpatterns = [
    url(r'^', include(router.urls))
]

View .py

class UserProfileViewSet(viewsets.ModelViewSet):
    """
    This viewset automatically provides `list`, `create`, `retrieve`,
    `update` and `destroy` actions.
    """
    queryset = UserProfile.objects.all()
    serializer_class = UserProfileSerializer
    permission_classes = (permissions.IsAuthenticatedOrReadOnly,
                          IsOwnerOrReadOnly,)
    pagination_class = LimitTenPagination

    @detail_route(renderer_classes=[renderers.JSONRenderer])
    def perform_create(self, serializer):
        serializer.save(user=self.request.user)


class UserViewSet(viewsets.ReadOnlyModelViewSet):
    """
    This viewset automatically provides `list` and `detail` actions
    """
    queryset = User.objects.all()
    serializer_class = UserSerializer

来自我的 models.py 的片段

class UserProfile(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE, related_name='profile')

我试过的:

我尝试更改 user-detail至 api:user-detail (是的 api 命名空间确实存在于主 urls.py 文件中)

Answer 1

查看文档，我相信您必须使用 HyperLinkedRelatedField .另见 this related SO post .

您在序列化程序字段定义中混淆了参数。我认为应该是:

class UserSerializer(serializers.ModelSerializer):
    url = serializers.HyperlinkedRelatedField(view_name='api:userprofile-detail',
                                              source='profile')

编辑 :

已添加 namespace api