php - 计算两个日期之间的夜数

Question

我想如何提取确切的夜晚数。我试图通过两种方式实现这一点，但不起作用。它返回 20 晚，但实际上是 21 晚(3 月有 31 天)

$startTimeStamp = strtotime("14-03-2017");                                   
$endTimeStamp = strtotime("04-04-2017");                                     

$timeDiff = abs($endTimeStamp - $startTimeStamp);                            

$numberDays = $timeDiff/86400;  // 86400 seconds in one day                  


$numberDays = intval($numberDays);                                           

echo $numberDays;                                                            

echo floor((strtotime('04-04-2017')-strtotime('14-03-2017'))/(60*60*24));    

Answer 1

使用新的 DateTime 扩展 PHP 5.3+:

$date1 = new DateTime("2010-07-06");
$date2 = new DateTime("2010-07-09");

// this calculates the diff between two dates, which is the number of nights
$numberOfNights= $date2->diff($date1)->format("%a");