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javascript - 如何根据另一个下拉菜单选择的条件删除和添加下拉列表值?

转载 作者:行者123 更新时间:2023-12-04 12:01:57 24 4
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我的要求:
我必须创建一个包含两个选择下拉列表的表单行,最后添加和删除按钮
1. 第一个下拉列表将包含 ed.. ['one', 'two', 'three','four'] 的值列表
2. 第二个下拉菜单将有条件 ['and','or']
假设选择表单值的第一行,例如 ['one'] ['and'] 然后单击添加按钮,然后将创建第二行。这里的第一个下拉列表不应该显示“一”值,因为条件是“和”。如果用户选择,那么它应该是所有值。对于我必须以 Angular 创建逻辑的所有行都是相似的。
HTML 代码:

<div class="state-filter-conditions-grid subs-model-sec filter-grid" *ngFor="let filterCondition of filters;  index as i">
<!-- OUTPUT PROPERTY -->

<ng-container *ngTemplateOutlet="filterView == 'subscription'? attrs: map; context: { index: i }"></ng-container>


<!-- CONNECTOR CONDITION -->
<div class="dt-attr valueCondition ctrl-condition minimal">
<div class="abs-cheveron select-box-cheveron">
<select class="state-select" [(ngModel)]="filters[i].op">
<option *ngFor="let val of op" [value]="val">{{val}}</option>
</select>
</div>

</div>
<!-- INPUT -->
<ng-container *ngTemplateOutlet="filterView != 'subscription'? attrs: map; context: { index: i }"></ng-container>
<!-- SELECT -->
<div class="dt-attr icons center-align">
<select class="ctrl-condition" *ngIf="!(i==filters.length-1)" [(ngModel)]="filters[i].logop" (change)="operatorChange(filters[i])">
<option *ngFor="let val of logop" [value]="val">{{val}}</option>
</select>

</div>
<!-- ICONS -->

<div class="dt-attr icons center-align">
<button *ngIf="i==filters.length-1" class="add-btn" (click)="addStateConditionRow()"><i
class="fa fa-sm fa-plus add-icon" aria-hidden="true"></i></button>
<button *ngIf="i>0" class="delete-btn" (click)="deleteStateConditionRow(i)"><i
class="fa fa-sm fa-trash delete-icon"></i></button>
</div>
</div>

<ng-template #attrs let-i="index">
<div class="dt-attr ">
<ng-container *ngIf="!dataProps">
<input class="ctrl-attr" type="text" [(ngModel)]="filters[i].value">
</ng-container>
<ng-container *ngIf="dataProps">
<select class="value-select" [(ngModel)]="filters[i].value">
<option *ngFor="let data of dataProps" [value]="data.attrId">{{data.attrName}}</option>
</select>
</ng-container>
</div>
</ng-template>

<ng-template #map let-i="index">
<div class="dt-attr ctrl-condition minimal">
<input class="ctrl-attr" type="text" clickOutside (clickOutside)="closeAccordion($event)" (click)="openAccordion($event)" [(ngModel)]="filters[i].attribute">
<div *ngIf="showAccordion" class="state-filter-accordion" style="position: absolute;
top: 105%;
width: 100%;z-index:1">
<app-common-accordion-mapping [filterInputRef]="filterInputRef" [inputAttributes]='inputAttributes' ></app-common-accordion-mapping>
</div>
</div>
</ng-template>

你们能帮我实现这一目标吗?
提前致谢。

最佳答案

我认为您正在寻找的是根据特定逻辑动态填充下拉列表。 This stackoverflow 的答案涵盖了 AngularJS 和 a stackoverflow question + blog对于 Angular 8 。但是,我无法帮助您处理业务逻辑本身,因为我不清楚。

关于javascript - 如何根据另一个下拉菜单选择的条件删除和添加下拉列表值?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68076662/

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