gpt4 book ai didi

r - ggplot2 - 关闭与另一个几何图形具有相同美感的几何图形的图例

转载 作者:行者123 更新时间:2023-12-04 11:58:42 25 4
gpt4 key购买 nike

我正在用两个不同的几何图形绘制一个图,都使用填充。我希望一个 geom 有一个传奇,但另一个没有。但是添加 show.legend=F到所需的 geom 不会关闭该 geom 的图例。

示例:

library(tidyverse)
library(ggalluvial)

x = tibble(qms = c("grass", "cereal", "cereal"),
move1 = "Birth",
move2 = c("Direct", "Market", "Slaughter"),
move3 = c("Slaughter", "Slaughter", NA),
freq = c(10, 5, 7))

x %>%
mutate(id = qms) %>%
to_lodes_form(axis = 2:4, id = id) %>%
na.omit() %>%
ggplot(aes(x = x, stratum = stratum, alluvium = id,
y = freq, label = stratum)) +
scale_x_discrete(expand = c(.1, .1)) +
geom_flow(aes(fill = qms)) +
geom_stratum(aes(fill = stratum), show.legend=F) +
geom_text(stat = "stratum", size = 3) +
theme_void() +
labs(fill="")

输出:

Output from code

所需输出:

Desired output

问题:

如何关闭一个几何图形的填充图例,而不是另一个几何图形?我可以(如果必须的话)在inkscape/gimp 中执行此操作,但更喜欢我可以进行版本控制的解决方案。

最佳答案

看看最后一行代码:

scale_fill_discrete(breaks = c("grass", "cereal")) 

这将填充的中断定义为仅包括 cerealgrass , 按要求。

library(tidyverse)
library(ggalluvial)

x = tibble(qms = c("grass", "cereal", "cereal"),
move1 = "Birth",
move2 = c("Direct", "Market", "Slaughter"),
move3 = c("Slaughter", "Slaughter", NA),
freq = c(10, 5, 7))

x %>%
mutate(id = qms) %>%
to_lodes_form(axis = 2:4, id = id) %>%
na.omit() %>%
ggplot(aes(x = x, stratum = stratum, alluvium = id,
y = freq, label = stratum)) +
scale_x_discrete(expand = c(.1, .1)) +
geom_flow(aes(fill = qms)) +
geom_stratum(aes(fill = stratum), show.legend=FALSE) +
geom_text(stat = "stratum", size = 3) +
theme_void() +
labs(fill="") +
scale_fill_discrete(breaks = c("grass", "cereal")) #<- This line!



创建于 2019-03-18 由 reprex package (v0.2.1)

关于r - ggplot2 - 关闭与另一个几何图形具有相同美感的几何图形的图例,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55219669/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com