Case 标签不会缩减为 C 中的整数常量？

Question

我正在开发一个游戏，我运行我的代码并收到错误“case label does not reduce to an integer constant”。我想我知道这意味着什么，但我该如何解决呢？这是我的代码:

#include<stdio.h>
#include<stdlib.h

int player_cash[3] = {50};
char job[][20] {
    'A',
    'B',
    'C',
    "Donate",
    "Go to work",
    "Exit"
};
int jobs;

int main()
{
    while(player_cash[0] > 0) {
        printf("Please type A, B, C, Donate, Go to work, or Exit\n");
        switch(jobs) {

            case 'A':
            player_cash[0]-=5;
            player_cash[1]+=5;
            printf("Cash=%i\n\n", player_cash[0]);
            continue;

            case 'B':
            player_cash[0]-=5;
            player_cash[2]+=5;
            printf("Cash=%i\n\n", player_cash[0]);
            continue;

            case 'C':
            player_cash[0]-=5;
            player_cash[3]+=5;
            printf("Cash=%i\n\n", player_cash[0]);
            continue;

            case "Donate":
            player_cash[0]-=15; //Error here
            player_cash[1]+=5;
            player_cash[2]+=5;
            player_cash[3]+=5;
            printf("Cash donated\n\n");
            printf("Cash=%i\n\n", player_cash[0]);
            continue;

            case "Go to work":
            player_cash[0]+=10; //Error here
            printf("Work done\n\n");
            printf("Cash=%i\n\n", player_cash[0]);
            continue;

            case "Exit":
            printf("Thanks for playing!\n\n"); //Error here
            break;

            default:
            printf("Does not compute");
            continue;
        }
    }
        getchar();
        return 0;
}

所以，我希望用户做的是输入其中一个选项，然后执行与之对应的操作。我该如何解决这个问题？

Answer 1

您不能将字符串用作 case 表达式:

case "Donate":

只能使用整数表达式，例如case 'A': 没问题。

概念上你有问题:jobs 是一个 int，而你正在测试字符串。如果你想让用户输入字符串(超过一个字符)，你需要保留一个字符串变量，并使用类似 fgets 的东西来获取整行输入。