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scala - Spark DataFrame 不尊重模式并将所有内容视为字符串

转载 作者:行者123 更新时间:2023-12-04 11:35:27 24 4
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我正面临一个我多年来一直无法克服的问题。

  • 我使用的是 Spark 1.4 和 Scala 2.10。我现在无法升级(大型分布式基础架构)
  • 我有一个包含几百列的文件,其中只有 2 个是字符串,其余都是 Long。我想将此数据转换为标签/特征数据框。
  • 我已经能够将其转换为 LibSVM 格式。
  • 我只是无法将其转换为标签/功能格式。

  • 原因是
  • 我无法使用这里显示的 toDF()
    https://spark.apache.org/docs/1.5.1/ml-ensembles.html
    val data = MLUtils.loadLibSVMFile(sc, "data/mllib/sample_libsvm_data.txt").toDF()

    它在 1.4 中不支持
  • 所以我首先将 txtFile 转换成一个 DataFrame ,在那里我使用了这样的东西
    def getColumnDType(columnName:String):StructField = {

    if((columnName== "strcol1") || (columnName== "strcol2"))
    return StructField(columnName, StringType, false)
    else
    return StructField(columnName, LongType, false)
    }
    def getDataFrameFromTxtFile(sc: SparkContext,staticfeatures_filepath: String,schemaConf: String) : DataFrame = {
    val sfRDD = sc.textFile(staticfeatures_filepath)//
    val sqlContext = new org.apache.spark.sql.SQLContext(sc)
    // reads a space delimited string from application.properties file
    val schemaString = readConf(Array(schemaConf)).get(schemaConf).getOrElse("")

    // Generate the schema based on the string of schema
    val schema =
    StructType(
    schemaString.split(" ").map(fieldName => getSFColumnDType(fieldName)))

    val data = sfRDD
    .map(line => line.split(","))
    .map(p => Row.fromSeq(p.toSeq))

    var df = sqlContext.createDataFrame(data, schema)

    //schemaString.split(" ").drop(4)
    //.map(s => df = convertColumn(df, s, "int"))

    return df
    }

  • 当我做 df.na.drop() df.printSchema()使用这个返回的数据框,我得到了完美的架构,就像这样

    root
    |-- rand_entry: long (nullable = false)
    |-- strcol1: string (nullable = false)
    |-- label: long (nullable = false)
    |-- strcol2: string (nullable = false)
    |-- f1: long (nullable = false)
    |-- f2: long (nullable = false)
    |-- f3: long (nullable = false)
    and so on till around f300

    但是 - 可悲的部分是我尝试用 df 做的任何事情(见下文),我总是收到 ClassCastException(java.lang.String 不能转换为 java.lang.Long)
    val featureColumns = Array("f1","f2",....."f300")
    assertEquals(-99,df.select("f1").head().getLong(0))
    assertEquals(-99,df.first().get(4))
    val transformeddf = new VectorAssembler()
    .setInputCols(featureColumns)
    .setOutputCol("features")
    .transform(df)

    所以 - 不好的是 - 即使模式说 Long - df 仍然在内部将所有内容视为字符串。

    编辑

    添加一个简单的例子

    说我有一个这样的文件

    1,A,20,P,-99,1,0,0,8,1,1,1,1,131153
    1,B,23,P,-99,0,1,0,7,1,1,0,1,65543
    1,C,24,P,-99,0,1,0,9,1,1,1,1,262149
    1,D,7,P,-99,0,0,0,8,1,1,1,1,458759



    sf-schema=f0 strCol1 f1 strCol2 f2 f3 f4 f5 f6 f7 f8 f9 f10 f11

    (列名真的无关紧要,因此您可以忽略此详细信息)

    我想要做的就是创建一个标签/特征类型的数据框,其中我的第 3 列成为标签,第 5 到第 11 列成为特征 [矢量] 列。这样我就可以按照 https://spark.apache.org/docs/latest/ml-classification-regression.html#tree-ensembles 中的其余步骤进行操作.

    我也像 zero323 建议的那样转换了列
    val types = Map("strCol1" -> "string", "strCol2" -> "string")
    .withDefault(_ => "bigint")
    df = df.select(df.columns.map(c => df.col(c).cast(types(c)).alias(c)): _*)
    df = df.drop("f0")
    df = df.drop("strCol1")
    df = df.drop("strCol2")

    但是断言和 VectorAssembler 仍然失败。
    featureColumns = Array("f2","f3",....."f11")
    这是我拥有 df 后想做的整个序列
        var transformeddf = new VectorAssembler()
    .setInputCols(featureColumns)
    .setOutputCol("features")
    .transform(df)

    transformeddf.show(2)

    transformeddf = new StringIndexer()
    .setInputCol("f1")
    .setOutputCol("indexedF1")
    .fit(transformeddf)
    .transform(transformeddf)

    transformeddf.show(2)

    transformeddf = new VectorIndexer()
    .setInputCol("features")
    .setOutputCol("indexedFeatures")
    .setMaxCategories(5)
    .fit(transformeddf)
    .transform(transformeddf)

    来自 ScalaIDE 的异常跟踪 - 就在它遇到 VectorAssembler 时如下所示

    java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Long
    at scala.runtime.BoxesRunTime.unboxToLong(BoxesRunTime.java:110)
    at scala.math.Numeric$LongIsIntegral$.toDouble(Numeric.scala:117)
    at org.apache.spark.sql.catalyst.expressions.Cast$$anonfun$castToDouble$5.apply(Cast.scala:364)
    at org.apache.spark.sql.catalyst.expressions.Cast$$anonfun$castToDouble$5.apply(Cast.scala:364)
    at org.apache.spark.sql.catalyst.expressions.Cast.eval(Cast.scala:436)
    at org.apache.spark.sql.catalyst.expressions.Alias.eval(namedExpressions.scala:118)
    at org.apache.spark.sql.catalyst.expressions.CreateStruct$$anonfun$eval$2.apply(complexTypes.scala:75)
    at org.apache.spark.sql.catalyst.expressions.CreateStruct$$anonfun$eval$2.apply(complexTypes.scala:75)
    at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:244)
    at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:244)
    at scala.collection.mutable.ResizableArray$class.foreach(ResizableArray.scala:59)
    at scala.collection.mutable.ArrayBuffer.foreach(ArrayBuffer.scala:47)
    at scala.collection.TraversableLike$class.map(TraversableLike.scala:244)
    at scala.collection.AbstractTraversable.map(Traversable.scala:105)
    at org.apache.spark.sql.catalyst.expressions.CreateStruct.eval(complexTypes.scala:75)
    at org.apache.spark.sql.catalyst.expressions.CreateStruct.eval(complexTypes.scala:56)
    at org.apache.spark.sql.catalyst.expressions.ScalaUdf$$anonfun$2.apply(ScalaUdf.scala:72)
    at org.apache.spark.sql.catalyst.expressions.ScalaUdf$$anonfun$2.apply(ScalaUdf.scala:70)
    at org.apache.spark.sql.catalyst.expressions.ScalaUdf.eval(ScalaUdf.scala:960)
    at org.apache.spark.sql.catalyst.expressions.Alias.eval(namedExpressions.scala:118)
    at org.apache.spark.sql.catalyst.expressions.InterpretedMutableProjection.apply(Projection.scala:68)
    at org.apache.spark.sql.catalyst.expressions.InterpretedMutableProjection.apply(Projection.scala:52)
    at scala.collection.Iterator$$anon$11.next(Iterator.scala:328)
    at scala.collection.Iterator$$anon$11.next(Iterator.scala:328)
    at scala.collection.Iterator$$anon$10.next(Iterator.scala:312)
    at scala.collection.Iterator$class.foreach(Iterator.scala:727)
    at scala.collection.AbstractIterator.foreach(Iterator.scala:1157)
    at scala.collection.generic.Growable$class.$plus$plus$eq(Growable.scala:48)
    at scala.collection.mutable.ArrayBuffer.$plus$plus$eq(ArrayBuffer.scala:103)
    at scala.collection.mutable.ArrayBuffer.$plus$plus$eq(ArrayBuffer.scala:47)
    at scala.collection.TraversableOnce$class.to(TraversableOnce.scala:273)
    at scala.collection.AbstractIterator.to(Iterator.scala:1157)
    at scala.collection.TraversableOnce$class.toBuffer(TraversableOnce.scala:265)
    at scala.collection.AbstractIterator.toBuffer(Iterator.scala:1157)
    at scala.collection.TraversableOnce$class.toArray(TraversableOnce.scala:252)
    at scala.collection.AbstractIterator.toArray(Iterator.scala:1157)
    at org.apache.spark.sql.execution.SparkPlan$$anonfun$3.apply(SparkPlan.scala:143)
    at org.apache.spark.sql.execution.SparkPlan$$anonfun$3.apply(SparkPlan.scala:143)
    at org.apache.spark.SparkContext$$anonfun$runJob$5.apply(SparkContext.scala:1767)
    at org.apache.spark.SparkContext$$anonfun$runJob$5.apply(SparkContext.scala:1767)
    at org.apache.spark.scheduler.ResultTask.runTask(ResultTask.scala:63)
    at org.apache.spark.scheduler.Task.run(Task.scala:70)
    at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:213)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
    at java.lang.Thread.run(Thread.java:745)

    最佳答案

    你得到 ClassCastException因为这正是应该发生的事情。模式参数不用于自动转换(一些 DataSources 可能会以这种方式使用模式,但不是像 createDataFrame 这样的方法)。它只声明存储在行中的值的类型。您有责任传递与模式匹配的数据,而不是相反。

    虽然 DataFrame显示您声明的模式仅在运行时验证,因此运行时异常。如果您想将数据转换为特定的数据,您有 cast数据明确。

  • 首先将所有列读作 StringType :
    val rows = sc.textFile(staticfeatures_filepath)
    .map(line => Row.fromSeq(line.split(",")))

    val schema = StructType(
    schemaString.split(" ").map(
    columnName => StructField(columnName, StringType, false)
    )
    )

    val df = sqlContext.createDataFrame(rows, schema)
  • 接下来将选定的列转换为所需的类型:
    import org.apache.spark.sql.types.{LongType, StringType}

    val types = Map("strcol1" -> StringType, "strcol2" -> StringType)
    .withDefault(_ => LongType)

    val casted = df.select(df.columns.map(c => col(c).cast(types(c)).alias(c)): _*)
  • 使用汇编器:
    val transformeddf = new VectorAssembler()
    .setInputCols(featureColumns)
    .setOutputCol("features")
    .transform(casted)

  • 您可以使用 spark-csv 简单地执行第 1 步和第 2 步:
    // As originally 
    val schema = StructType(
    schemaString.split(" ").map(fieldName => getSFColumnDType(fieldName)))


    val df = sqlContext
    .read.schema(schema)
    .format("com.databricks.spark.csv")
    .option("header", "false")
    .load(staticfeatures_filepath)

    另见 Correctly reading the types from file in PySpark

    关于scala - Spark DataFrame 不尊重模式并将所有内容视为字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35990117/

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