javascript - JS拖拽: Dropping one element on top of another replaces dataTransfer data with first elements

Question

我正在编写一个带有反应的简单国际象棋游戏，并尝试使用拖放 API 来简化棋子的拖放。所有作品都按预期工作，除非一件作品捕捉到另一幅作品。例如，如果白车捕获黑兵，则白车移动到黑兵之前的位置，黑兵离开棋盘。但是下次我尝试移动白车时，它会移动被捕获的黑棋。
无论使用哪两个部分，此行为都是 100% 一致的。 Piece 1 捕获了piece 2，现在piece 1 的dataTransfer 数据就是piece2 的数据。
我已经缩小了范围，我认为问题在于 dataTransfer 对象。
棋子的dragStart代码

_onDragStart( e ){
    e.dataTransfer.items.clear();
    e.dataTransfer.clearData( "text/plain" );
    e.dataTransfer.effectAllowed = "move";
    e.dataTransfer.dropEffect = "move";
    e.dataTransfer.setData( "text/plain", JSON.stringify( this.metaData ) );
}

瓷砖放置处理程序的代码

_onDrop( e ){
    this.onDrop({
        index: this.state.index,
        piece: JSON.parse( e.dataTransfer.getData( "text/plain" ) )
    });
}

Answer 1

1) Try replace the old piece using dropBefore.replaceWith(yourNewChessPiece);

2) are you Missing the target element Id , not setting it, not sure if your metaData variable has it

一些 samples

// cache you element/variables to simplify the later
// I think you are missing this, I cant tell what your this.metaData holds
chessPieceToAddToTile = document.getElementById(data),
dropBefore = ev.target;

// using childNode.replaceWith() to insert the 
// so, *** REPLACE old piece with your new chessPieceToAddToTile Node
// dropBefore Node:
dropBefore.replaceWith(chessPieceToAddToTile);

childNode.replaceWith().... Ref和 Node.replaceChild().

Troubleshooting: Simplify it a bit so you can see what's happening, something like this in your drag handler, drop handlers

console.log("dragStart: dropEffect = " + ev.dataTransfer.dropEffect + " ; effectAllowed = " + ev.dataTransfer.effectAllowed ; chessPieceToAddToTile... blah blah);