json - 使用 GSON 将 JSON 解析为 Java POJO

Question

我在这里有一个非常直接的问题。我需要从 API 获取 JSON 并将其转换为我为它们创建的对象。

到目前为止，它会将它们反序列化到我的 List 中，但每个 Metric 对象都有空值

JSON 进来

{
"metrics": [
    {
        "metric": {
            "type": 1,
            "name": "slide-11-start",
            "value": "1287249598295",
            "sessionID": "" 
        } 
    },
    {
        "metric": {
            "type": 1,
            "name": "slide-21-start",
            "value": "1287249601368",
            "sessionID": "" 
        } 
    },
    {
        "metric": {
            "type": 7,
            "name": "resolution",
            "value": "1680x1050",
            "sessionID": "" 
        } 
    },
    {
        "metric": {
            "type": 6,
            "name": "OS",
            "value": "Linux",
            "sessionID": "" 
        } 
    },
    {
        "metric": {
            "type": 5,
            "name": "browser",
            "value": "Netscape",
            "sessionID": "" 
        } 
    } 
]

}

度量对象

public class Metric {

    private int type;
    private String name;
    private String value;
    private String sessionID;

    /**
     * @return the type
     */
    public int getType() {
        return type;
    }

    /**
     * @param type the type to set
     */
    public void setType(int type) {
        this.type = type;
    }

    /**
     * @return the name
     */
    public String getName() {
        return name;
    }

    /**
     * @param name the name to set
     */
    public void setName(String name) {
        this.name = name;
    }

    /**
     * @return the value
     */
    public String getValue() {
        return value;
    }

    /**
     * @param value the value to set
     */
    public void setValue(String value) {
        this.value = value;
    }

    /**
     * @return the sessionID
     */
    public String getSessionID() {
        return sessionID;
    }

    /**
     * @param sessionID the sessionID to set
     */
    public void setSessionID(String sessionID) {
        this.sessionID = sessionID;
    }

}

容器对象

import java.util.List;

/**
 *
 * @author joshua
 */
public class MetricSet {

    private List<Metric> metrics;

    /**
     * @return the metrics
     */
    public List<Metric> getMetrics() {
        return metrics;
    }

    /**
     * @param metrics the metrics to set
     */
    public void setMetrics(List<Metric> metrics) {
        this.metrics = metrics;
    }
}

转换 JSON 的代码

    String json = "";
    if(request.getParameter("data") != null) {
        json = request.getParameter("data");
    }

    MetricSet metrics = new MetricSet();

    try {
        Gson gson = new Gson();
        Type listType = new TypeToken<MetricSet>() {}.getType();
        metrics = gson.fromJson(json, MetricSet.class);
    }
    catch(Exception ex) {
        String msg = ex.toString();
    }

Answer 1

您可以为 JSON 对象创建相应的 java 类。 integer , string值可以按原样映射。 JSON 可以这样解析:

 Gson gson = new GsonBuilder().create();
 Response r = gson.fromJson(jsonString, Response.class);

这是一个例子: http://rowsandcolumns.blogspot.com/2013/02/url-encode-http-get-solr-request-and.html