r - 将儒略日转换为日/月/年

Question

我的帖子显然不清楚，所以我正在尝试修复它，如果我仍然不清楚，请随时告诉我!
我得到了一个物理变量的数据框，每分钟都有一个数据。我想将前 4 列转换为单个列:R 中的“%d/%m/%Y %H:%M”(GMT)。

Year    Julian_day  Hour    Minute  Air_temp    Water_temp  Rel_hum   Wind_int  Wind_dir
2012    1   0   0   11.82   4.73    87.2    5.1 310
2012    1   0   1   11.92   4.743   87.2    5   310
2012    1   0   2   11.86   4.748   86.9    4.7 310

Answer 1

# This imports your data into a variable named "weather"
weather <- read.table(text = "Year    Julian_day  Hour    Minute  Air_temp    Water_temp  Rel_hum   Wind_int  Wind_dir
2012    1   0   0   11.82   4.73    87.2    5.1 310
2012    1   0   1   11.92   4.743   87.2    5   310
2012    1   0   2   11.86   4.748   86.9    4.7 310", header = TRUE)

# Combine the first four columns into a character vector
date_info <- with(weather, paste(Year, Julian_day, Hour, Minute))
# Parse that character vector
strptime(date_info, "%Y %j %H %M")