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flutter - 如何在 Flutter 中将 List 保存到 SharedPreferences？
转载 作者：行者123 更新时间：2023-12-04 11:04:02 31 4
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我有一个最喜欢的音乐列表，我在第一次打开应用程序时从音乐中检索它，该应用程序从最喜欢的音乐列表中获取一个最喜欢的音乐列表。我想将此列表保存为共享

preferences.List<Music> favoriteMusic = new List<Music>();

音乐课在哪里: 
class Music {
  final int id;
  final String name, size, rating, duration, img;
  bool favorite;

  Music({
    this.id,
    this.rating,
    this.size,
    this.duration,
    this.name,
    this.img,
    this.favorite,
  });

  factory Music.fromJson(Map<String, dynamic> jsonData){
    return Music(
      id: jsonData['id'],
      rating: jsonData['rating'],
      size: jsonData['size'],
      duration: jsonData['duration'],
      name: jsonData['name'],
      img: jsonData['img'],
      favorite: false,
    );
  }
}

如何保存最喜欢的音乐列表？

最佳答案

你应该做这些步骤
保存对象:

  1. convert your object to map with toMap() method
  2. encode your map to string with encode(...) method
  3. save the string to shared preferences

用于恢复您的对象:
  1. decode shared preference string to a map with decode(...) method
  2. use fromJson() method to get your object


更新完整样本 
import 'dart:convert';

void main() async {
  final SharedPreferences prefs = await SharedPreferences.getInstance();
  
  // Encode and store data in SharedPreferences
  final String encodedData = Music.encode([
    Music(id: 1, ...),
    Music(id: 2, ...),
    Music(id: 3, ...),
  ]);

  await prefs.setString('musics_key', encodedData);

  // Fetch and decode data
  final String musicsString = await prefs.getString('musics_key');

  final List<Music> musics = Music.decode(musicsString);
}

class Music {
  final int id;
  final String name, size, rating, duration, img;
  bool favorite;

  Music({
    this.id,
    this.rating,
    this.size,
    this.duration,
    this.name,
    this.img,
    this.favorite,
  });

  factory Music.fromJson(Map<String, dynamic> jsonData) {
    return Music(
      id: jsonData['id'],
      rating: jsonData['rating'],
      size: jsonData['size'],
      duration: jsonData['duration'],
      name: jsonData['name'],
      img: jsonData['img'],
      favorite: false,
    );
  }

  static Map<String, dynamic> toMap(Music music) => {
        'id': music.id,
        'rating': music.rating,
        'size': music.size,
        'duration': music.duration,
        'name': music.name,
        'img': music.img,
        'favorite': music.favorite,
      };

  static String encode(List<Music> musics) => json.encode(
        musics
            .map<Map<String, dynamic>>((music) => Music.toMap(music))
            .toList(),
      );

  static List<Music> decode(String musics) =>
      (json.decode(musics) as List<dynamic>)
          .map<Music>((item) => Music.fromJson(item))
          .toList();
}

关于flutter - 如何在 Flutter 中将 List<Object> 保存到 SharedPreferences？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/61316208/

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