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sql - 看似简单的 SQL 查询结果非常复杂 (Oracle)

转载 作者:行者123 更新时间:2023-12-04 11:03:12 25 4
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我在这里展示了我遇到的一个问题的简化版本,我在 Oracle 10.2 上工作:

我为 children 管理圣诞礼物,我有一个 child 的 list ,以及一个根据 child 的年龄和性别准备的合适礼物的理论 list 。我还跟踪他们实际收到的礼物:

    drop table actual_presents;
drop table kids;
drop table intended_presents;

create table kids (
name varchar2(30),
sex varchar2(1),
constraint pk_kids primary key(name),
constraint kids_sex_check check (sex in ('M', 'F'))
);

insert into kids(name, sex) values ('Alice','F');
insert into kids(name, sex) values ('Bob','M');
insert into kids(name, sex) values ('Carol','F');
insert into kids(name, sex) values ('Dave','M');

commit;

create table intended_presents (
age number,
sex varchar2(1),
present varchar2(30),
constraint pk_intended_presents primary key(age, sex, present),
constraint present_sex_check check (sex in ('M', 'F'))
);

insert into intended_presents(age, sex, present) values (5,'F', 'Doll');
insert into intended_presents(age, sex, present) values (6,'F', 'Poney');
insert into intended_presents(age, sex, present) values (5,'M', 'Car');
insert into intended_presents(age, sex, present) values (6,'M', 'Soldier');

commit;

create table actual_presents (
age number,
kid varchar2(30),
present varchar2(30),
constraint pk_actual_presents primary key(age, kid, present),
constraint fk_ap_k foreign key(kid) references kids(name)
);

insert into actual_presents(age, kid, present) values (5, 'Alice', 'Doll');
insert into actual_presents(age, kid, present) values (6, 'Alice', 'Poney');
insert into actual_presents(age, kid, present) values (5, 'Bob', 'Car');
insert into actual_presents(age, kid, present) values (6, 'Bob', 'Soldier');
insert into actual_presents(age, kid, present) values (5, 'Carol', 'Car');
insert into actual_presents(age, kid, present) values (6, 'Carol', 'Poney');
insert into actual_presents(age, kid, present) values (5, 'Dave', 'Soldier');
insert into actual_presents(age, kid, present) values (6, 'Dave', 'Car');

commit;

我现在想要提取每个 child 的预期礼物和实际礼物之间的比较。只要每个 child 只收到一份礼物,就很简单:
    select 'Basic query: double join, works well with 1 present per christmas' as remark from dual;
select k.name, k.sex, ip.age, ip.present as intended_present, ap.present as actual_present
from kids k, intended_presents ip, actual_presents ap
where k.name = ap.kid
and k.sex = ip.sex
and ap.age = ip.age
order by k.name, ip.age, ip.present;

但是还有更复杂的情况:我们可以为给定的圣诞节安排几份礼物,或者应该收到 2 份礼物的 child 实际上可能会收到 1 或 3 份。
    insert into intended_presents(age, sex, present) values (5,'F', 'Drum');
insert into intended_presents(age, sex, present) values (6,'F', 'Orange');
insert into intended_presents(age, sex, present) values (5,'M', 'Itchy sweater');
insert into intended_presents(age, sex, present) values (6,'M', 'Coloring book');
insert into intended_presents(age, sex, present) values (7,'M', 'Trumpet');
insert into intended_presents(age, sex, present) values (7,'M', 'Apple');

insert into actual_presents(age, kid, present) values (5, 'Alice', 'Drum');
insert into actual_presents(age, kid, present) values (6, 'Alice', 'Orange');
insert into actual_presents(age, kid, present) values (5, 'Bob', 'Itchy sweater');
insert into actual_presents(age, kid, present) values (6, 'Bob', 'Coloring book');
insert into actual_presents(age, kid, present) values (5, 'Carol', 'Trumpet');
insert into actual_presents(age, kid, present) values (5, 'Dave', 'Coloring book');
insert into actual_presents(age, kid, present) values (6, 'Dave', 'Itchy sweater');
insert into actual_presents(age, kid, present) values (6, 'Dave', 'Puppy');

现在我发现不可能进行查询/ View 返回以下预期结果:
    NAME                   S    AGE ACTUAL_PRESENT         INTENDED_PRESENT
------------------------------ - ---------- ------------------------------ ------------------------------
Alice F 5 Doll Doll
Alice F 5 Drum Drum
Alice F 6 Orange Orange
Alice F 6 Poney Poney
Bob M 5 Car Car
Bob M 5 Itchy sweater Itchy sweater
Bob M 6 Coloring book Coloring book
Bob M 6 Soldier Soldier
Carol F 5 Car Doll
Carol F 5 Trumpet Drum
Carol F 6 Orange
Carol F 6 Poney Poney
Dave M 5 Coloring book Car
Dave M 5 Soldier Itchy sweater
Dave M 6 Car Coloring book
Dave M 6 Itchy sweater Soldier
Dave M 6 Puppy

17 rows selected.

前面描述的“简单”查询将返回多余的不需要的行,因为连接不再包含几个礼物(例如 Alice 5 Doll Doll 正确行 1 行,Alice 5 Doll Drum 1 行不正确)。

我最接近有效结果的是通过对行进行排名使用一些技巧,然后尝试仅提取正确的行,但仍然不适合预期的礼物列:
    select 'score + partition by rank' as remark from dual;
select name, sex, age, actual_present, intended_present from (
select name, sex, age, actual_present, intended_present, row_number() over (partition by name, sex, age, actual_present order by score desc) as rank
from (
select
(case when sq.actual_present = ip.present then 1
else 0
end) as score,
sq.name as name, nvl(sq.sex, ip.sex) as sex, nvl(sq.age, ip.age) as age, sq.actual_present, ip.present as intended_present
from (
select k.name, k.sex, ap.age, ap.present as actual_present
from kids k,actual_presents ap
where k.name = ap.kid
) sq
full outer join intended_presents ip
on ip.age = sq.age
and ip.sex = sq.sex
where name is not null
)
) where rank = 1
order by name, age, actual_present;

NAME S AGE ACTUAL_PRESENT INTENDED_PRESENT
------------------------------ - ---------- ------------------------------ ------------------------------
Alice F 5 Doll Doll
Alice F 5 Drum Drum
Alice F 6 Orange Orange
Alice F 6 Poney Poney
Bob M 5 Car Car
Bob M 5 Itchy sweater Itchy sweater
Bob M 6 Coloring book Coloring book
Bob M 6 Soldier Soldier
Carol F 5 Car Doll
Carol F 5 Trumpet *Doll*
Carol F 6 Poney Poney
Dave M 5 Coloring book Car
Dave M 5 Soldier *Car*
Dave M 6 Car Coloring book
Dave M 6 Itchy sweater *Coloring book*
Dave M 6 Puppy *Coloring book*

16 rows selected.

我尝试添加一个额外的列 present_index 以使连接自然,但这并不能解决问题,因为:
- 仅针对此 View 对数据模型进行了不必要的更改
- 它没有准确地描述现实(1 - 娃娃 + 2 - 鼓相当于 1 - 鼓 + 2 - 娃娃)
- 我们缺少额外礼物的行(Dave - 6 - Puppy - NULL)
    alter table intended_presents add present_index number;
update intended_presents set present_index = 1 where present in ('Doll', 'Car', 'Orange', 'Soldier', 'Apple');
update intended_presents set present_index = 2 where present_index is null;
commit;

alter table intended_presents drop constraint pk_intended_presents;
alter table intended_presents add constraint pk_intended_presents primary key(age, sex, present_index);
select * from intended_presents order by age, sex, present_index;

alter table actual_presents add present_index number;
update actual_presents set present_index = 1 where present in ('Doll', 'Car', 'Orange', 'Soldier');
update actual_presents set present_index = 3 where present in ('Puppy');
update actual_presents set present_index = 2 where present_index is null;
commit;
alter table actual_presents drop constraint pk_actual_presents;
alter table actual_presents add constraint pk_actual_presents primary key(age, kid, present_index);

select 'With present_index, we can use that in the join.' as remark from dual;
select k.name, k.sex, ip.age, ip.present as intended_present, ap.present as actual_present, ap.present_index
from kids k, intended_presents ip, actual_presents ap
where k.name = ap.kid
and k.sex = ip.sex
and ap.age = ip.age
and ap.present_index = ip.present_index
order by k.name, ip.age, ap.present_index;

NAME S AGE INTENDED_PRESENT ACTUAL_PRESENT PRESENT_INDEX
------------------------------ - ---------- ------------------------------ ------------------------------ -------------
Alice F 5 Doll Doll 1
Alice F 5 Drum Drum 2
Alice F 6 Orange Orange 1
Alice F 6 Poney Poney 2
Bob M 5 Car Car 1
Bob M 5 Itchy sweater Itchy sweater 2
Bob M 6 Soldier Soldier 1
Bob M 6 Coloring book Coloring book 2
Carol F 5 Doll Car 1
Carol F 5 Drum Trumpet 2
Carol F 6 Poney Poney 2
Dave M 5 Car Soldier 1
Dave M 5 Itchy sweater Coloring book 2
Dave M 6 Soldier Car 1
Dave M 6 Coloring book Itchy sweater 2

15 rows selected.


update actual_presents set present_index = 3 where kid = 'Alice' and present = 'Doll';
update actual_presents set present_index = 1 where kid = 'Alice' and present = 'Drum';
update actual_presents set present_index = 2 where kid = 'Alice' and present = 'Doll';
commit;

select k.name, k.sex, ip.age, ip.present as intended_present, ap.present as actual_present, ap.present_index
from kids k, intended_presents ip, actual_presents ap
where k.name = ap.kid
and k.sex = ip.sex
and ap.age = ip.age
and ap.present_index = ip.present_index
order by k.name, ip.age, ap.present_index;

NAME S AGE INTENDED_PRESENT ACTUAL_PRESENT PRESENT_INDEX
------------------------------ - ---------- ------------------------------ ------------------------------ -------------
Alice F 5 *Doll* *Drum* 1
Alice F 5 *Drum* *Doll* 2
Alice F 6 Orange Orange 1
Alice F 6 Poney Poney 2
Bob M 5 Car Car 1
Bob M 5 Itchy sweater Itchy sweater 2
Bob M 6 Soldier Soldier 1
Bob M 6 Coloring book Coloring book 2
Carol F 5 Doll Car 1
Carol F 5 Drum Trumpet 2
Carol F 6 Poney Poney 2
Dave M 5 Car Soldier 1
Dave M 5 Itchy sweater Coloring book 2
Dave M 6 Soldier Car 1
Dave M 6 Coloring book Itchy sweater 2

15 rows selected.

最后,我只设法从基于包的流水线函数创建了一个 View ,该函数实际上通过回溯计算了想要的值(如果需要,我可以发布代码)。
对于这个只有 3 个小 table 的简单问题,这似乎非常复杂且成本高昂。我在这里遗漏了一些明显的东西吗?

***************** 解决方案 https://stackoverflow.com/users/3486433/serpiton *****************

您的查询完美地显示了所有差异,我现在要做的就是添加实际 = 预期的行并且我的问题已解决
    WITH ActualNotIntended AS (
SELECT name, age, sex, present as actual
, Row_Number() OVER (Partition BY name, age ORDER BY present) as ID
FROM (SELECT k.name, a.age, k.sex, a.present
FROM kids k
INNER JOIN actual_presents a ON k.Name = a.kid
MINUS
SELECT k.name, i.age, k.sex, i.present
FROM kids k
INNER JOIN intended_presents i ON k.sex = i.sex) a
), IntendedNotActual AS (
SELECT name, age, sex, present as intended
, Row_Number() OVER (Partition BY name, age ORDER BY present) as ID
FROM (SELECT k.name, i.age, k.sex, i.present
FROM kids k
INNER JOIN intended_presents i ON k.sex = i.sex
INNER JOIN actual_presents a ON a.age = i.age AND k.sex = i.sex
MINUS
SELECT k.name, a.age, k.sex, a.present
FROM kids k
INNER JOIN actual_presents a ON k.Name = a.kid) i
), ActualIntended as(
SELECT k.name, a.age, k.sex, a.present as actual, i.present as intended
FROM kids k
JOIN actual_presents a ON k.name = a.kid
JOIN intended_presents i ON k.sex = i.sex AND i.age = a.age AND i.present = a.present
)
SELECT Coalesce(a.name, i.name) as name
, Coalesce(a.age, i.age) as age
, Coalesce(a.sex, i.sex) as sex
, actual
, intended
FROM ActualNotIntended a
FULL JOIN IntendedNotActual i
ON a.name = i.name AND a.age = i.age
AND a.sex = i.sex AND a.id = i.id
UNION
SELECT name, age, sex, actual, intended
FROM ActualIntended
ORDER by name, age, actual;

NAME AGE S ACTUAL INTENDED
------------------------------ ---------- - ------------------------------ ------------------------------
Alice 5 F Doll Doll
Alice 5 F Drum Drum
Alice 6 F Orange Orange
Alice 6 F Poney Poney
Bob 5 M Car Car
Bob 5 M Itchy sweater Itchy sweater
Bob 6 M Coloring book Coloring book
Bob 6 M Soldier Soldier
Carol 5 F Car Doll
Carol 5 F Trumpet Drum
Carol 6 F Poney Poney

NAME AGE S ACTUAL INTENDED
------------------------------ ---------- - ------------------------------ ------------------------------
Carol 6 F Orange
Dave 5 M Coloring book Car
Dave 5 M Soldier Itchy sweater
Dave 6 M Car Coloring book
Dave 6 M Itchy sweater Soldier
Dave 6 M Puppy

17 rows selected.

作为记录,这比我想要的基于函数的 View 更简单、可读和可维护:
    DROP TYPE V_RECORD_TABLE;
DROP TYPE V_RECORD;
CREATE OR REPLACE TYPE V_RECORD AS OBJECT (
NAME VARCHAR2(30),
SEX VARCHAR2(1),
AGE NUMBER,
ACTUAL_PRESENT VARCHAR2(30),
INTENDED_PRESENT VARCHAR2(30)
);
/
CREATE OR REPLACE TYPE V_RECORD_TABLE AS TABLE OF V_RECORD;
/


CREATE OR REPLACE PACKAGE INTENDED_VS_ACTUAL AS
FUNCTION GET_DATA RETURN V_RECORD_TABLE PIPELINED;
END INTENDED_VS_ACTUAL;
/

CREATE OR REPLACE PACKAGE BODY INTENDED_VS_ACTUAL AS

TYPE REF_CURSOR IS REF CURSOR;
/* types to record intended presents */
TYPE LIST_OF_IP_REC IS TABLE OF VARCHAR2(30);
TYPE LIST_OF_IP_PER_AGE IS TABLE OF LIST_OF_IP_REC INDEX BY PLS_INTEGER; /* index per age */
TYPE LIST_OF_IP IS TABLE OF LIST_OF_IP_PER_AGE INDEX BY VARCHAR2(1); /* index per sex */

TYPE EXPECTED_USED IS TABLE OF NUMBER INDEX BY VARCHAR2(30);


FUNCTION TREAT_PENDING(PENDING_ACTUAL IN OUT LIST_OF_IP_REC, EXP_USED IN OUT EXPECTED_USED, CUR_KID IN VARCHAR2, CUR_AGE IN NUMBER, CUR_SEX VARCHAR2) RETURN V_RECORD_TABLE
IS
CUR_EXPECTED VARCHAR2(30) := '';
CUR_EXPECTED_SELECTED VARCHAR2(30) := '';
V_REC V_RECORD_TABLE := V_RECORD_TABLE();
BEGIN
IF PENDING_ACTUAL.LAST > 0 THEN
DBMS_OUTPUT.PUT_LINE('pending actual has '||PENDING_ACTUAL.LAST||' items');
FOR i IN PENDING_ACTUAL.FIRST .. PENDING_ACTUAL.LAST
LOOP
DBMS_OUTPUT.PUT_LINE('pending actual '||PENDING_ACTUAL(i));
CUR_EXPECTED_SELECTED := NULL;
CUR_EXPECTED := EXP_USED.FIRST;
WHILE CUR_EXPECTED IS NOT NULL
LOOP
DBMS_OUTPUT.PUT_LINE('checking exp used item '||CUR_EXPECTED||' with value '||EXP_USED(CUR_EXPECTED));
IF EXP_USED(CUR_EXPECTED) = 0 THEN
EXP_USED(CUR_EXPECTED) := 1;
CUR_EXPECTED_SELECTED := CUR_EXPECTED;
END IF;
EXIT WHEN CUR_EXPECTED_SELECTED IS NOT NULL;
CUR_EXPECTED := EXP_USED.NEXT(CUR_EXPECTED);
END LOOP; -- loop on expected used
IF CUR_EXPECTED_SELECTED IS NOT NULL THEN
DBMS_OUTPUT.PUT_LINE('returning row with actual '||PENDING_ACTUAL(i)||' exp used selected '||CUR_EXPECTED_SELECTED);
V_REC.EXTEND;
V_REC(V_REC.LAST) := V_RECORD(CUR_KID, CUR_SEX, CUR_AGE, PENDING_ACTUAL(i), CUR_EXPECTED_SELECTED);
ELSE
DBMS_OUTPUT.PUT_LINE('returning row with actual '||PENDING_ACTUAL(i)||' exp used selected NULL');
V_REC.EXTEND;
V_REC(V_REC.LAST) := V_RECORD(CUR_KID, CUR_SEX, CUR_AGE, PENDING_ACTUAL(i), NULL);
END IF;
END LOOP; -- loop on pending actual
END IF; -- if pending actual

/* remaining unused expected */
DBMS_OUTPUT.PUT_LINE('checking remaining unused expected');
CUR_EXPECTED := EXP_USED.FIRST;
WHILE CUR_EXPECTED IS NOT NULL
LOOP
-- DBMS_OUTPUT.PUT_LINE('checking exp used item '||CUR_EXPECTED||' with value '||EXP_USED(CUR_EXPECTED));
IF EXP_USED(CUR_EXPECTED) = 0 THEN
EXP_USED(CUR_EXPECTED) := 1;
V_REC.EXTEND;
V_REC(V_REC.LAST) := V_RECORD(CUR_KID, CUR_SEX, CUR_AGE, NULL, CUR_EXPECTED);
DBMS_OUTPUT.PUT_LINE('returning row with actual NULL exp used selected '||CUR_EXPECTED);
END IF;
CUR_EXPECTED := EXP_USED.NEXT(CUR_EXPECTED);
END LOOP; -- loop on expected used
RETURN V_REC;
END TREAT_PENDING;


FUNCTION GET_DATA RETURN V_RECORD_TABLE
PIPELINED
IS
V_REC V_RECORD_TABLE;

/* variables to fetch records */
CUR REF_CURSOR;
CUR_SEX VARCHAR2(1);
CUR_AGE NUMBER;
CUR_PRESENT VARCHAR2(30);
CUR_KID VARCHAR2(30);
IP_LIST LIST_OF_IP;
/* TREATMENT VARS */
PREV_KID VARCHAR2(30) := '';
PREV_AGE NUMBER := -1;
PREV_SEX VARCHAR2(1) := '';

i NUMBER;
PENDING_ACTUAL LIST_OF_IP_REC := LIST_OF_IP_REC();

EXP_USED EXPECTED_USED;
AP_FOUND BOOLEAN := FALSE;
BEGIN
/* first record intended presents by age, sex */
OPEN CUR FOR SELECT SEX, AGE, PRESENT FROM INTENDED_PRESENTS;
LOOP
FETCH cur INTO cur_sex, cur_age, cur_present;
EXIT WHEN CUR%NOTFOUND;
IF NOT IP_LIST.EXISTS(CUR_SEX) THEN
IP_LIST(CUR_SEX)(CUR_AGE) := LIST_OF_IP_REC();
END IF;
IF NOT IP_LIST(CUR_SEX).EXISTS(CUR_AGE) THEN
IP_LIST(CUR_SEX)(CUR_AGE) := LIST_OF_IP_REC();
END IF;
IP_LIST(CUR_SEX)(CUR_AGE).EXTEND;
IP_LIST(CUR_SEX)(CUR_AGE)(IP_LIST(CUR_SEX)(CUR_AGE).LAST) := CUR_PRESENT;
END LOOP;
CLOSE CUR;
DBMS_OUTPUT.PUT_LINE('intended presents recorded');

/* Treat actual presents */
OPEN CUR FOR SELECT K.NAME, K.SEX, AP.AGE, AP.PRESENT AS ACTUAL_PRESENT
FROM KIDS K, ACTUAL_PRESENTS AP
WHERE K.NAME = AP.KID ORDER BY K.NAME, AP.AGE;
LOOP
FETCH CUR INTO CUR_KID, CUR_SEX, CUR_AGE, CUR_PRESENT;
EXIT WHEN CUR%NOTFOUND;
DBMS_OUTPUT.PUT_LINE('********** actual present record kid '||CUR_KID||' sex '||CUR_SEX||' age '||CUR_AGE||' present '||CUR_PRESENT||' *********');
IF NOT IP_LIST.EXISTS(CUR_SEX) THEN
RAISE_APPLICATION_ERROR(-1, 'unknown sex '||CUR_SEX);
END IF;
IF NOT IP_LIST(CUR_SEX).EXISTS(CUR_AGE) THEN
RAISE_APPLICATION_ERROR(-2, 'unknown age for sex '||CUR_SEX||': '||CUR_AGE);
END IF;

IF (CUR_KID <> PREV_KID OR CUR_AGE <> PREV_AGE) THEN
DBMS_OUTPUT.PUT_LINE('switching kid or age, from '||PREV_KID||'/'||PREV_AGE||' to '||CUR_KID||'/'||CUR_AGE);
IF PREV_AGE > -1 THEN
/* here send rows from collected data */
DBMS_OUTPUT.PUT_LINE('Checking for pending records...');
V_REC := TREAT_PENDING(PENDING_ACTUAL, EXP_USED, PREV_KID, PREV_AGE, PREV_SEX);
DBMS_OUTPUT.PUT_LINE('Found records to return: '||V_REC.LAST);
IF V_REC.LAST IS NOT NULL THEN
FOR i IN V_REC.FIRST .. V_REC.LAST
LOOP
PIPE ROW ( V_REC(i));
END LOOP;
END IF;
END IF; -- if prev_age > 1 i.e. had something before, to ensure not executed on first row

/* here reinit variables */
PENDING_ACTUAL.DELETE;
EXP_USED.DELETE;
END IF; -- if switch kid / age
PREV_KID := CUR_KID;
PREV_AGE := CUR_AGE;
PREV_SEX := CUR_SEX;
/* Check whether actual present has been returned, store in pending list if not */
AP_FOUND := FALSE;
FOR i IN IP_LIST(CUR_SEX)(CUR_AGE).FIRST .. IP_LIST(CUR_SEX)(CUR_AGE).LAST
LOOP
IF CUR_PRESENT = IP_LIST(CUR_SEX)(CUR_AGE)(i) THEN
DBMS_OUTPUT.PUT_LINE('match found for '||CUR_PRESENT||' at index '||i||' marking '||IP_LIST(CUR_SEX)(CUR_AGE)(i)||' as used');
EXP_USED(IP_LIST(CUR_SEX)(CUR_AGE)(i)) := 1;
PIPE ROW ( V_RECORD( CUR_KID, CUR_SEX, CUR_AGE, CUR_PRESENT, IP_LIST(CUR_SEX)(CUR_AGE)(i) ) );
AP_FOUND := TRUE;
ELSE
IF NOT EXP_USED.EXISTS(IP_LIST(CUR_SEX)(CUR_AGE)(i)) THEN
EXP_USED(IP_LIST(CUR_SEX)(CUR_AGE)(i)) := 0;
DBMS_OUTPUT.PUT_LINE(IP_LIST(CUR_SEX)(CUR_AGE)(i)||' marked as not used');
END IF;
END IF;
END LOOP; -- loop of intended presents
IF NOT AP_FOUND THEN
DBMS_OUTPUT.PUT_LINE('no match found for '||CUR_PRESENT||' in intended list. storing in pending_actual');
PENDING_ACTUAL.EXTEND;
PENDING_ACTUAL(PENDING_ACTUAL.LAST) := cur_present;
END IF;


END LOOP; -- loop on actual presents from query

V_REC := TREAT_PENDING(PENDING_ACTUAL, EXP_USED, CUR_KID, CUR_AGE, CUR_SEX); -- treat remaining data for last kid/age group of rows
IF V_REC.LAST IS NOT NULL THEN
FOR i IN V_REC.FIRST .. V_REC.LAST
LOOP
PIPE ROW ( V_REC(i));
END LOOP;
END IF;

RETURN;
END GET_DATA;

END INTENDED_VS_ACTUAL;
/


CREATE OR REPLACE VIEW V_INTENDED_VS_ACTUAL AS SELECT * FROM TABLE(INTENDED_VS_ACTUAL.GET_DATA());
SELECT * FROM V_INTENDED_VS_ACTUAL ORDER BY NAME, AGE, ACTUAL_PRESENT;

NAME S AGE ACTUAL_PRESENT INTENDED_PRESENT
------------------------------ - ---------- ------------------------------ ------------------------------
Alice F 5 Doll Doll
Alice F 5 Drum Drum
Alice F 6 Orange Orange
Alice F 6 Poney Poney
Bob M 5 Car Car
Bob M 5 Itchy sweater Itchy sweater
Bob M 6 Coloring book Coloring book
Bob M 6 Soldier Soldier
Carol F 5 Car Doll
Carol F 5 Trumpet Drum
Carol F 6 Poney Poney
Carol F 6 Orange
Dave M 5 Coloring book Car
Dave M 5 Soldier Itchy sweater
Dave M 6 Car Soldier
Dave M 6 Itchy sweater Coloring book
Dave M 6 Puppy

最佳答案

我认为您的问题在于您的数据模型。您在 child 餐 table 上没有任何 child 的年龄,因此您只有将 table 绑在一起的性别。因此,您得到的是每个 child 的预期礼物和实际礼物的所有可能组合,因为给给定年龄和性别的 child 准备的礼物数量不一定是他们实际收到的礼物数量。

年龄在 actual_presents 表中根本不合适,这应该只是 child 和礼物之间的联系。您当前的设计将面临的问题是,您无法根据年龄和性别列出每个 child 有资格收到的礼物 list ,因为您与 child 的年龄没有关系,您只有在两个不同的表格中重复了当前的预期目标年龄。如果我了解您的要求,并且您完全可以更改设计,我会建议如下:

CREATE TABLE kids(KidID number, Name varchar2(30), Sex varchar2(1), Age number);
CREATE TABLE presents(PresentID number, TargetAge number, Sex varchar2(1), Present varchar2(30));
CREATE TABLE actual_presents(ActualPresentId number, KidID number, PresentID number);

这将允许您像这样存储 child 的详细信息:
insert into kids(KidID, Name, Sex, Age) values (1, 'Alice','F', 6);
insert into kids(KidID, Name, Sex, Age) values (2, 'Bob','M', 7);
insert into kids(KidID, Name, Sex, Age) values (3, 'Carol','F', 5);
insert into kids(KidID, Name, Sex, Age) values (4, 'Dave','M', 5);

insert into presents(PresentID, TargetAge, sex, present) values (1, 5,'F', 'Drum');
insert into presents(PresentID, TargetAge, sex, present) values (2, 6,'F', 'Orange');
insert into presents(PresentID, TargetAge, sex, present) values (3, 5,'M', 'Itchy sweater');
insert into presents(PresentID, TargetAge, sex, present) values (4, 6,'M', 'Coloring book');
insert into presents(PresentID, TargetAge, sex, present) values (5, 7,'M', 'Trumpet');
insert into presents(PresentID, TargetAge, sex, present) values (6, 7,'M', 'Apple');
insert into presents(PresentID, TargetAge, sex, present) values (7, 5,'F', 'Doll');
insert into presents(PresentID, TargetAge, sex, present) values (8, 6,'F', 'Pony');
insert into presents(PresentID, TargetAge, sex, present) values (9, 5,'M', 'Car');
insert into presents(PresentID, TargetAge, sex, present) values (10, 6,'M', 'Soldier');
insert into presents(PresentID, TargetAge, sex, present) values (11, 7,'F', 'Puppy');

insert into actual_presents(ActualPresentID, KidID, PresentID) values (1, 1, 7);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (2, 1, 8);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (3, 2, 9);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (4, 2, 10);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (5, 3, 9);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (6, 3, 8);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (7, 4, 10);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (8, 4, 9);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (9, 1, 1);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (10, 1, 2);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (11, 2, 3);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (12, 2, 4);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (13, 3, 5);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (14, 4, 4);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (15, 4, 3);
insert into actual_presents(ActualPresentID, KidID, PresentID) values (16, 4, 11);

现在你真的需要有两个查询(无论你改变表格结构还是注释,这都适用):一个显示 child 可以根据年龄和性别收到的礼物,一个显示他们实际得到的礼物。
/*Possible presents per child based on gender and age*/
select k.name, k.sex S, k.age KidAge, p.Present
from kids k
inner join presents p
on p.targetage = k.age
and p.sex = k.sex
order by k.name asc;

/*Actual presents received by each child*/
select k.name, k.sex S, k.age KidAge, p.TargetAge, p.present
from Kids k
inner join actual_presents ap
on ap.KidID = k.KidID
inner join presents p
on p.PresentID = ap.PresentID
Order by k.name asc;

那有意义吗?为任何类型或格式错误道歉,当我真正应该工作时,我在 SQL Server 中这样做了!

关于sql - 看似简单的 SQL 查询结果非常复杂 (Oracle),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23809713/

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