r - 如何在tibble列中找到最长的重复序列？

Question

我更新了我的问题，因为我的输出表还需要一列。

我有以下小标题:

library(tibble)

my_tbl <- tribble(
  ~year, ~event_id, ~winner_id, 
  2011,      "A",     4322,
  2012,      "A",     4322,
  2013,      "A",     4322,
  2014,      "A",     5478,
  2015,      "A",     4322,
  2011,      "B",     4322,
  2012,      "B",     7893,
  2013,      "B",     7893,
  2014,      "B",     2365,
  2015,      "B",     3407,
  2011,      "C",     5556,
  2012,      "C",     5556,
  2013,      "C",     1238,
  2014,      "C",     2391,
  2015,      "C",     2391,
  2011,      "D",     4219,
  2012,      "D",     7623,
  2013,      "D",     8003,
  2014,      "D",     2851,
  2015,      "D",     0418
)

我想通过事件 ID 找出连续获胜次数最多的一次。我正在寻找的结果如下所示:

results_summary_tbl <- tribble(
~event_id, ~most_wins_in_a_row, ~number_of_winners, ~winners, ~years,
"A", 3, 1, "4322", "4322 = (2011, 2012, 2013)",
"C", 2, 2, "5556, 2391", "5556 = (2011, 2012), 2391 = (2014, 2015)",
"B", 2, 1, "7893", "7893 = (2012, 2013)",
"D", 1, 5, "4219, 7623, 8003, 2851, 0418", "4219 = (2011), 7623 = (2012), 8003 = (2013), 2851 = (2015), (2018), ”
)

谢谢

Answer 1

一 dplyr选项可以是:

my_tbl %>%
 add_count(event_id, rleid = cumsum(winner_id != lag(winner_id, default = first(winner_id)))) %>%
 group_by(event_id) %>%
 summarise(most_wins_in_a_row = max(n),
           number_of_winners = n_distinct(winner_id[n == max(n)]),
           winners = paste0(unique(winner_id[n == max(n)]), collapse = ","))

  event_id most_wins_in_a_row number_of_winners winners                
  <chr>                 <int>             <int> <chr>                  
1 A                         3                 1 4322                   
2 B                         2                 1 7893                   
3 C                         2                 2 5556,2391              
4 D                         1                 5 4219,7623,8003,2851,418