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scala - 无法在 Akka Stream 中使用 GraphStage 类运行 SourceShape

转载 作者:行者123 更新时间:2023-12-04 11:00:18 24 4
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我正在尝试使用 GraphStage 构造创建一个 Redis Akka 流源。这个想法是,每当我从 subscribe 方法获得更新时,我都会将其推送到下一个组件。此外,如果没有拉动信号,则组件应背压。这是代码:

class SubscriberSourceShape(channel: String, subscriber: Subscriber) 
extends GraphStage[SourceShape[String]] {

private val outlet: Outlet[String] = Outlet("SubscriberSource.Out")

override def shape: SourceShape[String] = SourceShape(outlet)

override def createLogic(inheritedAttributes: Attributes): GraphStageLogic = {
new GraphStageLogic(shape) {
val callback = getAsyncCallback((msg: String) => push(outlet, msg)
val handler = (msg: String) => callback.invoke(msg)

override def preStart(): Unit = subscriber.subscribe(channel)(handler)
}
}
}

但是,当我用一个简单的接收器运行它时,我收到了这个错误:
Error in stage [akka.http.impl.engine.server.HttpServerBluePrint$ProtocolSwitchStage@58344854]: No handler defined in stage [...SubscriberSourceShape@6a9193dd] for out port [RedisSubscriberSource.Out(1414886352). All inlets and outlets must be assigned a handler with setHandler in the constructor of your graph stage logic.
怎么了?

最佳答案

您收到此错误是因为您尚未为 Source 设置任何输出处理程序,因此当下游组件(Flow 或 Sink)向此 Source 发送拉取信号时,没有处理程序来处理拉取信号。

您可以添加一个 OutputHandler 来消除错误。将 onPull 方法留空,因为您是在 asyncCallback 上生成元素。只需在 GraphStageLogic 主体中添加以下内容:

      setHandler(outlet, new OutHandler {
override def onPull(): Unit = {}
})

关于scala - 无法在 Akka Stream 中使用 GraphStage 类运行 SourceShape,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58847650/

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