sql - t-SQL 查找每个组的前 10 条记录

Question

我想弄清楚如何为每组 Trans.TranSID 返回前 10 条记录。

SELECT a.ABID, a.ABName, t.TranSID, SUM(IIF(TranTypeID = 'CO', td.Qty * CAST(td.Price AS money) * - 1, 
                      td.Qty * CAST(td.Price AS money))) AS TotalSales
FROM         Trans t INNER JOIN
                      TransDetail td ON t.TranID = td.TranID INNER JOIN
                      ABook a ON t.TranABID = a.ABID
WHERE     (t.TranDate BETWEEN CONVERT(DATETIME, '2012-01-01 00:00:00', 102) AND CONVERT(DATETIME, '2013-01-01 00:00:00', 102)) AND 
           t.TranTypeID in ('SO','CA','CO') AND (t.TranStatus <> 'V')
GROUP BY a.ABID, a.ABName, t.TranSID
HAVING  (NOT (a.ABName LIKE '%cash%'))
ORDER BY t.TranSID, TotalSales Desc

我可以将“TOP 10”添加到 select 语句中，但这会为我提供前 10 个帐户，而不考虑组。 Trans.TranSID 有 25 组，我试图只为每个组获得前 10 名。

Answer 1

我认为您正在寻找 ROW_NUMBER()与 PARTITION BY

SELECT * 
FROM (
    SELECT 
        ROW_NUMBER() OVER(PARTITION BY t.TranSID ORDER BY t.TranSID, SUM(IIF(TranTypeID = 'CO', td.Qty * CAST(td.Price AS money) * - 1, td.Qty * CAST(td.Price AS money))) DESC) as RowNum,            
        a.ABID, 
        a.ABName, 
        t.TranSID, 
        SUM(IIF(TranTypeID = 'CO', td.Qty * CAST(td.Price AS money) * - 1, td.Qty * CAST(td.Price AS money))) AS TotalSales
    FROM Trans t 
       INNER JOIN TransDetail td 
           ON t.TranID = td.TranID 
       INNER JOIN ABook a 
           ON t.TranABID = a.ABID
    WHERE (t.TranDate BETWEEN CONVERT(DATETIME, '2012-01-01 00:00:00', 102) AND CONVERT(DATETIME, '2013-01-01 00:00:00', 102)) 
       AND t.TranTypeID in ('SO','CA','CO')
       AND (t.TranStatus <> 'V')
    GROUP BY a.ABID, a.ABName, t.TranSID
    HAVING  (NOT (a.ABName LIKE '%cash%'))
) a
WHERE a.RowNum <=10

这将为分组中的每条记录分配一个行号(由 PARTITION 定义的列，从 1 到 n。从那里，您可以在其上运行 SELECT 以获取每组任意数量的记录。