python - 有没有更简洁的方法来构建这个列表？ python 3

Question

我想知道是否有更简洁的方法来执行我的代码的第 3 部分？
我正在为分配构建一个井字游戏，这是检查是否有一行 3 个 X 或 O 的函数。因此，我将代表 3x3 游戏板的“棋盘”列表拆分为三个列表，分别代表行、列和“角到角”线。

def check_forwin(board,split_list):

    #part 1 splice a single list into 3 lists
    check_list1 = [tuple(board[i:j]) for i, j in zip([1]+ split_list, split_list)]
    #part 2"invert" the list, as in choosing columns 
    check_list2 = list(zip(check_list1[0],check_list1[1],check_list1[2]))

    #part 3 make 2 lists from "corner to corner"
    check_list3 = [[],[]]

    check_list3[0] = tuple([check_list1[0][0],check_list1[1][1],check_list1[2][2]])
    check_list3[1] = tuple([check_list1[0][2],check_list1[1][1],check_list1[2][0]])

    return 

board = ["#","a","b","c","d","e","f","g","h","i"]
split_list1 = [4, 7, 10]

check_forwin(board,split_list1)

[('a', 'b', 'c'), ('d', 'e', 'f'), ('g', 'h', 'i')]
[('a', 'd', 'g'), ('b', 'e', 'h'), ('c', 'f', 'i')]
[('a', 'e', 'i'), ('c', 'e', 'g')]

Answer 1

使用列表理解使它更整洁，但是，正如 Kalma 所说，“整洁”是非常主观的。

def check_forwin(board,split_list):

    #part 1 splice a single list into 3 lists
    check_list1 = [tuple(board[i:j]) for i, j in zip([1]+ split_list, split_list)]

    #part 2"invert" the list, as in choosing columns 
    check_list2 = list(zip(check_list1[0],check_list1[1],check_list1[2]))

    #part 3 make 2 lists from "corner to corner"
    check_list3 = [[],[]]

    # Number of element in row or column
    n = len(check_list1)
    check_list3[0] = tuple([check_list1[i][i] for i in range(n)])
    check_list3[1] = tuple([check_list1[i][n-i-1] for i in range(n)])

    return