bash - 我需要一些关于 SRT 字幕文本处理的想法

Question

标题说明了我真正需要的 ATM。
基本上我已经创建了一个基于 Tesseract 和 ImageMagick 的 OCR 工具链。我已经设法使输出文本非常一致。我正在使用它对一些旧的硬字幕视频进行 OCR，并将它们制作成软字幕 SRT 字幕。为了获取图像输入的屏幕截图，我使用了我很久以前发现并重写的旧 shell 脚本的修改版本。这些被输入到第二个脚本中，该脚本将它们处理成 Tessaract 可读的形式。在这一点上，我可以轻松地手动完成剩余的工作，但如果可能的话，我想自动化除最终校对之外的所有工作。
示例文本(来自当前项目)

03:04.418  Their parents have always written    letters thanking us. =  
03:05.018  Their parents have always written    letters thanking us. =  
03:05.619  Their parents have always written    letters thanking us. =  
03:06.219  Their parents have always written    letters thanking us. =  
03:06.820  Their parents have always written    letters thanking us. =  
03:07.421  Their parents have always written    letters thanking us. =  
03:08.021  Their parents have always written    letters thanking us. =  
03:08.622  This seminary was highly reeemmended.    | am relieved te leave her in your care. =  
03:09.222  This seminary was highly reeemmended.    | am relieved te leave her in your care. =  
03:09.823  This seminary was highly reeemmended.    | am relieved te leave her in your care. =  
03:10.424  This seminary was highly reeemmended.    | am relieved te leave her in your care. =  
03:11.024  This seminary was highly reeemmended.    | am relieved te leave her in your care. =  
03:11.625  This seminary was highly reeemmended.    | am relieved te leave her in your care. =  
03:12.225  In additien te all the previeus requests se far..."  
03:12.826  In additien te all the previeus requests se far..."  
03:13.427  In additien te all the previeus requests se far..."  
03:14.027  In additien te all the previeus requests se far..."  
03:14.628  In additien te all the previeus requests se far..."

基本上我想匹配文本并从第一行和最后一行中提取时间戳并将它们设置为 srt 格式

1
00:03:04,418 --> 00:03:08,021
Their parents have always written
letters thanking us. =  

2
00:03:08,622 --> 00:03:08,622
This seminary was highly reeemmended
| am relieved te leave her in your care. = 

3
00:03:12,225 --> 00:03:14,628
In additien te all the previeus requests se far..."

在这一点上，我认为它是一个单独的脚本。
基本上 sub.txt 在 sub.srt 中。然后做一个校对通行证。现在检测到的文本中有一些可变性，但它是最小的。我偶尔会被检测为 |或 [ ，它有时会在一些奇怪的极端情况下混淆 o 和 e。
2020 年 2 月 2 日编辑:
我进行了一些更改和调整，以进一步获得我想要的。到我的 shell 脚本和 Ivans。我已经消除了 ivans 脚本和我的脚本生成的空白子行。
更新处理和 ocr 脚本 BTW

#!/bin/bash -x
 
cd "$1"
mkdir ocr

for f in *.png ;
do
base="$(basename "$f" | cut -d "." -f 1,2)"
echo "$base"
if [[ -z "$2" ]] ; 
then
tran="$(convert "$f"  -separate -average  -crop +0+720 -threshold 11% -fill black -draw 'color 700,10 floodfill' +repage ocr/"$base".png)"
  
else
tran="$(convert "$f"  -separate -average  -crop +0+720 -negate -threshold 15% -fill white -draw 'color 700,10 floodfill' +repage ocr/"$base".png)"
  
fi 
$tran
cd ocr
magick mogrify -pointsize 50 -fill blue -draw 'text 1400,310 "L" ' +repage "$base".png
cd ..


done
cd ocr
for i in *.png ;
do base2="$(basename "$i" | cut -d "." -f 1,2 | cut -d ":" -f 2,3)"
tesseract "$i" stdout -c page_separator='' --psm 6 --oem 1 --dpi 300 | { tr '\n' ' '; tr -s  [:space:] ' ';  echo; } >> text.txt
echo "$base2""  " >> time.txt

done
awk '{printf ("%s", $0); getline < "text.txt"; print $0 }' time.txt >> out.txt
sed -i 's/|/I/g' out.txt
sed -i 's/\[/I/g' out.txt
#sed -i 's/L//g' out.txt
#sed -i 's/=//g' out.txt
sed -i 's/.$//' out.txt
sed -i 's/.$//' out.txt

while read line ; do
sed "/[[:alpha:]]/ !d" >> sub.txt
done <out.txt
exit

制作蓝色 L 的部分是确保每一行都包含用于时间戳匹配的内容。
更新的 IVAN SRT 脚本

#!/bin/bash -x

sub="$1"            # path to sub file
OLD=$IFS            # remember current delimiter
IFS=$'\n'           # set delimiter to the new line
raw=( $(cat $sub) ) # load sub into raw array
IFS=$OLD            # set default delimiter back

reset () {
    unset raw[0]        # remove 1-st item from array
    raw=( "${raw[@]}" ) # rearange array
}

output () {
   
    printf "00:$time1 --> 00:$time3\n$text1\n\n"
    
    }

speen () {
    time3=$time2
    reset
    test=( "${raw[@]::2}" ) # get two more items
    test2=( ${test[0]} )    # split 2-nd item
    time2=${test2[0]}       # get 2-nd timing
    text2=${test2[@]:1}     # get 2-nd text
    
    # if only one item in test than this is the end, return
    
            
    [[ "${test[1]}" ]] || { printf "00:$time1 --> 00:$time2\n$text1\n\n"; raw=; return; }
    #   compare,     speen more if match,  print ang go further if not 
    
    [[ "$text1" == "$text2" ]] && speen || output
}

N=1 # set counter
while [[ "${raw[@]}" ]]; do # loop through data
    echo $((N++))       # print and inc counter
    test1=( $raw )      # get 1-st item
    time1=${test1[0]}   # get 1-st timing
    text1=${test1[@]:1}
    # get 1-st text
    speen
done

我刚刚添加了第三个时间变量以将旧的 time2 值保存为 time3。基本上消除空白时间戳行破坏了他的匹配。我意识到 time2 是第一个不匹配的时间戳。所以我需要保存上一个循环中的前一个。因此 time3=$time2然后休息 time2 值。然后使用旧的time2(现在的time3)打印子字符串。

Answer 1

以此结束

#!/bin/bash

sub=file            # path to sub file
OLD=$IFS            # remember current delimiter
IFS=$'\n'           # set delimiter to the new line
raw=( $(cat $sub) ) # load sub into raw array
IFS=$OLD            # set default delimiter back

reset () {
    unset raw[0]        # remove 1-st item from array
    raw=( "${raw[@]}" ) # rearange array
}

output () {
    text1=${text1//|/I} # change | to I in text
    text1=${text1//[/I} # change [ to I in text
    printf "$time1 --> $time2\n$text1\n\n"    
}

speen () {
    reset
    test=( "${raw[@]::2}" ) # get two more items
    test2=( ${test[0]} )    # split 2-nd item
    time2=${test2[0]}       # get 2-nd timing
    text2=${test2[@]:1}     # get 2-nd text
    # if only one item in test than this is the end, return
    [[ "${test[1]}" ]] || { printf "$time1 --> $time2\n$text1\n\n"; raw=; return; }
    #   compare,     speen more if match,  print ang go further if not 
    [[ "$text1" == "$text2" ]] && speen || output
}

N=1 # set counter
while [[ "${raw[@]}" ]]; do # loop through data
    echo $((N++))       # print and inc counter
    test1=( $raw )      # get 1-st item
    time1=${test1[0]}   # get 1-st timing
    text1=${test1[@]:1} # get 1-st text
    speen
done