javascript - 防止 ReactJS 中的多个按钮颜色激活

Question

我有两个带有 ReactJS 和 SemanticUI 的按钮。每次单击时，背景颜色都会更改。我希望一次只激活一个按钮，这意味着如果点击红色按钮，则绿色按钮会停用，反之亦然，取回默认的白色背景色。现在可以同时单击两者并更改颜色。

这是我的组件:

export class BoutonRefus extends Component {
  constructor(props) {
    super(props);
    this.state = {
      button: true
    };
    this.handleClick = this.handleClick.bind(this);
  }

  handleClick() {
    this.setState({
      button: !this.state.button
    });
  }
  render() {
    return (
      <>
        <div
          className={
            this.state.button
              ? "ui button medium refus true"
              : "ui button medium refus false"
          }
          onClick={this.handleClick}
        ></div>
      </>
    );
  }
}

export class BoutonAccepte extends Component {
  constructor(props) {
    super(props);
    this.state = {
      button: true
    };
    this.handleClick = this.handleClick.bind(this);
  }

  handleClick() {
    this.setState({
      button: !this.state.button
    });
  }
  render() {
    return (
      <>
        <div
          className={
            this.state.button
              ? "ui button medium accepte true"
              : "ui button medium accepte false" && 
          }
          onClick={this.handleClick}
        ></div>
      </>
    );
  }
}

该组件在此处调用:

boutonAccepter(t) {
        return (
            <>
            <BoutonAccepte 
            className="ui button medium accepte true"
            onClick={() => {this.voter(true)}}
            text={t('flot.split.vote.accepter')}
                />
            </>
        )
    }

boutonRefuser(t) {
        return (
            <>
            <BoutonRefus 
            className="ui button medium refus true"
            onClick={() => {
                this.justifierRefus()
                this.voter(false)
            }}
            text={t('flot.split.vote.refuser')}
            />
            </>
        )
    }

Answer 1

您不需要类组件。只需使用 useState()为您的本地状态 Hook 并制作一个功能组件。此外，为每个按钮制作不同的组件似乎是多余的。试试这个，当然只是粘贴你的类名:)

  function Buttons(){
   const [selectedButton, setSelectedButton] = React.useState();

   return (
      <div>
          <button type="button" 
             className={selectedButton === "refuse" ? "active-classname" : "inactive-classname"}
             onClick={() => setSelectedButton("refuse")}>Refus</button>
          <button type="button" 
             className={selectedButton === "refuse" ? "active-classname" : "inactive-classname"}
             onClick={() => setSelectedButton("refuse")}>Accepte</button>
      </div>
   ); 
}