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java - Maven - 为java项目中的每个java包创建一个jar

转载 作者:行者123 更新时间:2023-12-04 10:39:37 25 4
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假设我有 3 个包,需要为每个包创建一个 jar,每个包只包含当前包中的内容。我的尝试是:

<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>2.4</version>
<executions>
<execution>
<id>first-jar</id>
<goals>
<goal>jar</goal>
</goals>
<configuration>
<classifier>first-jar</classifier>
<excludes>
<exclude>/maven.task.3/src/main/java/third/ThirdMain.java
</exclude>
<exclude>/maven.task.3/src/main/java/second/SecondMain.java
</exclude>
</excludes>
</configuration>
</execution>
<execution>
<id>second-jar</id>
<goals>
<goal>jar</goal>
</goals>
<configuration>
<classifier>second-jar</classifier>
<excludes>
<exclude>/maven.task.3/src/main/java/first/FirstMain.java
</exclude>
<exclude>/maven.task.3/src/main/java/third/ThirdMain.java
</exclude>
</excludes>
</configuration>
</execution>
</executions>
</plugin>

这确实创建了不同的 jar,但是里面的内容是相同的,这意味着排除子句不起作用。我尝试只排除类(相对/绝对路径)和包。不要问我为什么这样做是为了作业,这没有多大意义!
这是我尝试做的方式,如果有其他更有效的方式,请随时与我分享!

编辑:不得使用模块化结构,它必须是一个单独的项目。

提前致谢

最佳答案

它已经在评论中得到了回答,但这里有一个例子。

父pom:

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>

<groupId>com.essexboy</groupId>
<artifactId>parent</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>pom</packaging>

<modules>
<module>jar1</module>
<module>jar2</module>
</modules>

</project>

和 2 个子/模块 poms,只有 artifactId 不同:
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>

<parent>
<artifactId>parent</artifactId>
<groupId>com.essexboy</groupId>
<version>1.0-SNAPSHOT</version>
</parent>

<artifactId>jar1</artifactId>

<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.11</version>
<scope>test</scope>
</dependency>
</dependencies>

<build>
</build>
</project>

额外信息

我使用以下命令创建了父级:
mvn archetype:generate -DarchetypeGroupId=org.codehaus.mojo.archetypes -DarchetypeArtifactId=pom-root -DarchetypeVersion=RELEASE

然后用命令创建了2个模块
mvn archetype:generate -DarchetypeGroupId=org.apache.maven.archetypes -DarchetypeArtifactId=maven-archetype-quickstart -DarchetypeVersion=RELEASE

如果你必须有一个 jar 项目(没有模块和父项目),你可以使用 shade-plugin :
<?xml version="1.0" encoding="UTF-8"?>

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>

<groupId>com.essexboy</groupId>
<artifactId>double-jar</artifactId>
<version>1.0-SNAPSHOT</version>

<name>double-jar</name>

<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.11</version>
<scope>test</scope>
</dependency>
</dependencies>

<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-shade-plugin</artifactId>
<version>3.2.1</version>
<executions>
<execution>
<id>1</id>
<phase>package</phase>
<goals>
<goal>shade</goal>
</goals>
<configuration>
<finalName>jar1</finalName>
<filters>
<filter>
<artifact>*:*</artifact>
<excludes>
<exclude>com/essexboy/App2*</exclude>
</excludes>
</filter>
</filters>
</configuration>
</execution>
<execution>
<id>2</id>
<phase>package</phase>
<goals>
<goal>shade</goal>
</goals>
<configuration>
<finalName>jar2</finalName>
<filters>
<filter>
<artifact>*:*</artifact>
<excludes>
<exclude>com/essexboy/App1*</exclude>
</excludes>
</filter>
</filters>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>

关于java - Maven - 为java项目中的每个java包创建一个jar,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59987286/

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