python - Pygame Sprite 二段跳

Question

所以我对 pygame 比较陌生，并且已经开始从基础教程分支出来。我希望 Sprite 能够进行二段跳并尝试添加变量等，因此如果他们最终获得加电或某种形式，我可以将其更改为三段跳，并且我可以轻松更改它，但我挣扎。 P.S:由于某些代码已被删除，某些评论可能没有意义，但对我仍然有用。

x = 200
y = 450
width = 64
height = 66
vel = 5
screenwidth = 500
isjump = True #whether our character is jumping or not
jumpcount = 10
maxjump = 2 #double jump
maxjumpcount = 0

#we must keep track of direction, are they moving and how many steps for frames

left = False
right = False
walkcount = 0


def redrawGameWindow():
    global walkcount

    window.blit(background,(0,0)) #loads bg at 0,0

    if  walkcount +1 >= 15: #15 as we have 5 sprites, which will be displayed 3 times per second
        walkcount = 0

    if left:
        window.blit(walkleft[walkcount//3],(x,y))#excludes remainders
        walkcount+=1
    elif right:
        window.blit(walkright[walkcount//3],(x,y))
        walkcount+=1
    elif isjump:
        window.blit(jumpp,(x,y))
        walkcount+=1
    else:
        window.blit(char,(x,y))

    pygame.display.update()


#now to write main loop which checks for collisions, mouse events etc
run = True
while run: #as soon as we exit this, the game ends
    #main loop, gonna check for collision

    clock.tick(15) #frame rate, how many pics per second, games r just a ton of pictures running very quickly
    #now we check for events

    for event in pygame.event.get(): #gets a list of all events that happened
        print(event)
                                    #can go through these events& check if they've happened
        if event.type == pygame.QUIT: #if we try to exit the window
            run = False

   through the use of events. If a key has been pressed, we change the x & y of our shape
    #if we want it to continuely move, we need to get a list



    keys = pygame.key.get_pressed() #if these are pressed or held down, execute whatever is under these.


    if keys[pygame.K_LEFT] and x > vel-vel: #if pressed we move our character by the velocity in whatever direction via grid which works from the TOP LEFT of screen
        #0,0 is top left           #vel-vel to equal 0, makes border better
        x -= vel
        left = True
        right = False
    elif keys[pygame.K_RIGHT] and x < screenwidth - width: #as the square co ord is top left of it
        x+= vel
        right = True
        left = False
    else:
        right = False
        left = False
        walkcount = 0

   #JUMP CODE
    if not(isjump): # still lets them move left and right
        if keys[pygame.K_SPACE]:
            isjump = True #quadratic function for jump
            right = False
            left = False
            walkcount = 0
            maxjumpcount+=1
            if maxjumpcount > 2:
                isjump = False
    else:
        while jumpcount >= -10 and maxjumpcount < 2: #moving slower, then faster, hang, then go down
            pygame.time.delay(12)
            y -= (jumpcount*abs(jumpcount)) / 2#1.35? #squared, 10 ^2, /2, jumpcount = jump height
            jumpcount -= 1


        else: #jump has concluded if it reaches here
            isjump = False
            jumpcount = 10
            maxjumpcount = 0 #double jump resets once jump ends

    redrawGameWindow()

为相当可悲的尝试道歉。任何其他建议将不胜感激，因为我还有很多东西要学。谢谢。

Answer 1

你有一个游戏循环，使用它。跳跃不需要额外的循环。使用选择 ( if ) 而不是内部 while循环，解决问题:

run = True
while run: #as soon as we exit this, the game ends
    # [...]

    if not(isjump): # still lets them move left and right
        if keys[pygame.K_SPACE]:
            # [...]
    else:

        # instead of: while jumpcount >= -10 and maxjumpcount < 2: 
        if jumpcount >= -10 and maxjumpcount < 2: # <---------------

            y -= (jumpcount*abs(jumpcount)) / 2
            jumpcount -= 1

请注意，此代码块在主应用程序循环中不断调用。