javascript - 切换大小写以检查字符串是否包含子字符串

Question

我有一个字符串，想检查是否有带有 switch/case 的子字符串。 fnstringCheck 返回 true例如，如果 fnstring 是 dies_ist_ein_test_diagnosen_erfassen .

怎么了？谢谢你的提示

 var fnstring = (interim_transcript).toLowerCase().replace(/ /gi, "_");

 console.log('fnstring:', fnstring)
 var fnstringCheck = fnstring.indexOf("diagnosen_erfassen") !== -1;
 console.log(fnstringCheck)

 switch (fnstring) {
    case (fnstring.indexOf("_arztbrief_analysieren") !== -1):
        $('.analyzesBtn').trigger('click');
        break;

    case (fnstring.indexOf("_einleitung_erfassen") !== -1):
        changeSection('einleitung', mergedSource);
        break;

    case (fnstring.indexOf("diagnosen_erfassen") !== -1):
         changeSection('einleitung', mergedSource);
         break;

        ...

Answer 1

您需要带true在 switch statement ，因为案例返回 true或 false .该支票使用 Identity/strict equality operator === .

var fnstring = (interim_transcript).toLowerCase().replace(/ /gi, "_");

console.log('fnstring:', fnstring)
var fnstringCheck = fnstring.indexOf("diagnosen_erfassen") !== -1;
console.log(fnstringCheck)

switch (true) { // strict comparison
    case fnstring.indexOf("_arztbrief_analysieren") !== -1:
        $('.analyzesBtn').trigger('click');
        break;

    case fnstring.indexOf("_einleitung_erfassen") !== -1:
        changeSection('einleitung', mergedSource);
        break;

    case fnstring.indexOf("diagnosen_erfassen") !== -1:
        changeSection('einleitung', mergedSource);
        break;
}