python - 如何将列表的值插入嵌套列表？

Question

我有这样的嵌套列表:

ll =
[[[0, 0.01655718859584843],
  [1, 0.03777621092166489],
  [2, 0.02162311536578436],
  [3, 0.02907007584458954]],
 [[0, 0.011912058415296719],
  [1, 0.07967490411502279],
  [2, 0.04067120278932331],
  [3, 0.05439173103552319]]]

我想在第二个列表中插入条目:

uu =
[4577911, 4577821]

到相应子列表的索引 0 中。

所以进入 ll的第一个子列表我想插入 uu 的第一个条目像这样:

[[[4577911, 0, 0.01655718859584843],
  [4577911, 1, 0.03777621092166489],
  [4577911, 2, 0.02162311536578436],
  [4577911, 3, 0.02907007584458954]],
 [[4577821, 0, 0.011912058415296719],
  [4577821, 1, 0.07967490411502279],
  [4577821, 2, 0.04067120278932331],
  [4577821, 3, 0.05439173103552319]]]

但是我的代码提供了奇怪的结果

tu = ([[[u + x] for x in t] for t in ll for u in uu])

我怎样才能正确地做到这一点？

Answer 1

在 zip 中使用嵌套列表理解

例如:

ll = [[[0, 0.01655718859584843],
  [1, 0.03777621092166489],
  [2, 0.02162311536578436],
  [3, 0.02907007584458954]],
  [[0, 0.011912058415296719],
  [1, 0.07967490411502279],
  [2, 0.04067120278932331],
  [3, 0.05439173103552319]]]

uu = [4577911, 4577821]

print([[[i] + k for k in j] for i, j in zip(uu, ll)])

输出:

[[[4577911, 0, 0.01655718859584843],
  [4577911, 1, 0.03777621092166489],
  [4577911, 2, 0.02162311536578436],
  [4577911, 3, 0.02907007584458954]],
 [[4577821, 0, 0.011912058415296719],
  [4577821, 1, 0.07967490411502279],
  [4577821, 2, 0.04067120278932331],
  [4577821, 3, 0.05439173103552319]]]