Python int 太大而无法转换为 C int，二进制转换为 ASCII

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我不能解码此消息:01010010010001010101001101010101010001010100110001010100010011110010110101010100010000010101001001000101010000010011001000101101010011000100111101000111010010010100001101000001001011010100001000110010001100000011001000110000

我想试试这个，但我无法解决它。它说“Python int 太大而无法转换为 C int”

 binaryString = input("Code: ")

bValues = binaryString.split(" ")
string = ""
for bValue in bValues:
    integer = int(bValue, 2)
    character = chr(integer)
    string += character

print ("The message is: ")
print ("")
print(string)
print ("")
print ("Thanks!")
a1 = input("Press enter to exit.")
if a1 in ("x"):
    exit()

Answer 1

输入是一个长字符串，您需要将其拆分为 8 个字符的组，而不是按空格拆分，这将创建一个包含整个输入的大小为 1 的列表

binaryString = input("Code: ").strip()

size = 8
bValues = [binaryString[i:i+size] for i in range(0, len(binaryString), size)]
string = ""
for bValue in bValues:
    integer = int(bValue, 2)
    character = chr(integer)
    string += character

输出

The message is: 

RESUELTO-TAREA2-LOGICA-B2020

Thanks!