java - 将 Yaml 属性对象转换为 Java 对象

Question

这是我的 Yaml 属性文件

bb:
  employees:
   -
    employee1:
      name: Syed
      locations:
        - HYD
        - MAA
   -
    employee2:
      name: Adhil
      locations:
        - BOM
        - DEL

我想在我的应用程序中将对象转换为我的 POJO。但是我做不到，它总是返回null。

有什么我想念的吗？

@Data

@Builder
 @AllArgsConstructor
@NoArgsConstructor
@Configuration
@ConfigurationProperties(prefix = "bb")
public class EmpConfig {

    EmployeeDetails employees;
}

EmployeeDetails 类

@Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
@Configuration

public class EmployeeDetails {

    List<Map<String, List<String>>> details;
}

Answer 1

它以这种方式为我工作:

YAML(称为application.yaml)(在employeeIds(employee1，employee2)之前删除了破折号)

bb:
  employees:
    employee1:
      name: Syed
      locations:
        - HYD
        - MAA
    employee2:
      name: Adhil
      locations:
        - BOM
        - DEL

配置类:

@Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
@Configuration
@ConfigurationProperties(prefix = "bb")
public class EmpConfig {
    private Map<String, EmployeeDetails> employees;
}

员工详情:

@Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
public class EmployeeDetails {
    private String name;
    private List<String> locations;
}

所以基本上你的语法和数据类型都有问题，所以 Spring 无法解析配置文件。