javascript - 检查延迟后元素是否仍然有 mouseenter

Question

我用 mouseenter 和 mouseleave 制作了一些积木

<button onMouseEnter={this.MouseEnter}>hover</button>

MouseEnter(e) {
    setTimeout(() => {
        //check if mouse over still on this element 
        // do action
    }, 600);
}

问题是当我非常快速地移动 block 时，最后一个 block 在超时之前检测到鼠标输入并执行操作，即使我没有悬停在 block 上这是一个错误，我想让它只运行操作在 block 上悬停 500 毫秒 之后。

p.s: 我正在使用 react.js

Answer 1

您真正缺少的部分是在触发 mouseLeave 事件时超时回调的失效。为此，您需要保留返回的 setTimeout 值，以便在计时器到期(或者组件卸载!!)之前调用 clearTimeout )

以下是基于类的组件中的基 native 制:

state = {
  hovered: false
};
timer;

mouseEnterHandler = () => this.setState({ hovered: true });
mouseLeaveHandler = () => this.setState({ hovered: false });

onTimeout = () => {
  // Do action
};

clearTimer = () => {
  clearTimeout(this.timer);
};

// Here's the meat:
// If state updates, then componentDidUpdate is called,
// if the new hovered state is true, set timeout and save the
// returned reference, else clear the timeout using the saved
// timer reference.

componentDidUpdate() {
  const { hovered } = this.state;

  if (hovered) {
    this.timer = setTimeout(this.onTimeout, 500);
  } else {
    this.clearTimer();
  }
}

// This is component cleanup, if the component unmounts before
// the timer expires you may not want the "Do action" to fire,
// so we go ahead and clear the timeout so you're not accidentally
// accessing state/props of an unmounted component.

componentWillUnmount() {
  this.clearTimer();
}

以下是等效的功能组件逻辑:

const [hovered, sethovered] = useState(false);

const mouseEnterHandler = () => sethovered(true);
const mouseLeaveHandler = () => sethovered(false);

const onTimeout = () => {
  // Do action
};

useEffect(() => {
  const timer = hovered && setTimeout(onTimeout, 500);
  return () => {
    clearTimeout(timer);
  };
}, [hovered]);