r - 在整个分隔符处拆分，但不是分隔符的每个组成部分

Question

我想拆分一个字符串并保留它被拆分的位置。

str = 'Glenn: $53  Sutter: $44'
strsplit(str, '[0-9]\\s+[A-Z]', perl = TRUE)
# [[1]]
# [1] "Glenn: $5"  "utter: $44" ## taking out what was matched
strsplit(str, '(?=[0-9]\\s+[A-Z])', perl = TRUE)
# [[1]]
# [1] "Glenn: $5"     "3"             "  Sutter: $44" ## splitting at each component of the match

有没有办法在整个定界符处分割它？所以它返回:

# [1] "Glenn: $53"  "Sutter: $44"

Answer 1

我们可以使用正则表达式环视在大写字母之前和数字之后分割一个或多个空格( \\s+ )

strsplit(str, "(?<=[0-9])\\s+(?=[A-Z])", perl = TRUE)[[1]]
#[1] "Glenn: $53"  "Sutter: $44"