python - 如何在保留标题的同时翻转 csv 行顺序？

Question

我希望能够翻转 csv 文件行但保留标题。

当前的

timestamp       open      high       low     close     volume
2020-04-14 2805.1001 2851.8501 2805.1001 2846.0601 3113388741
2020-04-13 2782.4600 2782.4600 2721.1699 2761.6299 5274310000
 .....
2000-01-04 1455.2200 1455.2200 1397.4301 1399.4200 1009000000
2000-01-03 1469.2500 1478.0000 1438.3600 1455.2200 931800000

想要的结果

timestamp       open      high       low     close     volume
2000-01-03 1469.2500 1478.0000 1438.3600 1455.2200 931800000
2000-01-04 1455.2200 1455.2200 1397.4301 1399.4200 1009000000
.....
2020-04-13 2782.4600 2782.4600 2721.1699 2761.6299 5274310000
2020-04-14 2805.1001 2851.8501 2805.1001 2846.0601 3113388741

我已经能够用这个翻转数据，但我不能保留标题。添加跳过标题，否则标题将放在 csv 文件的底部。

当前代码

 def reverse_csv():
    with open("spx.csv", "r") as infile, open("spx_cleaned.csv", "w") as outfile:
    reader = csv.reader(infile)
    next(reader, None)  # skip the headers
    writer = csv.writer(outfile)
    for row in reversed(list(reader)):
        # process each row
        writer.writerow(row)

谢谢!

Answer 1

您可以尝试以下方法吗？

pd.read_csv('input.csv').iloc[::-1].to_csv('output.csv', index=False)