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r - 基于日期范围的不同行

转载 作者:行者123 更新时间:2023-12-04 10:08:07 25 4
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我有一个大型数据集,其结构如下所示:

structure(list(pathogen = c("MRSA", "L. pneumophila", "MRSA", 
"L. pneumophila", "MRSA", "MRSA", "MRSA", "L. pneumophila", "L. pneumophila",
"MRSA"), variant = c("mecA", "sg1", "mecA", "sg1", "mecA", "mecC",
"mecA", "sg1", "sg6", "mecA"), n = c(25L, 14L, 235L, 2L, 64L,
15L, 13L, 6L, 11L, 8L), date = structure(c(15156, 15248, 15279,
15279, 15309, 15340, 15340, 15400, 15431, 15461), class = "Date")), .Names = c("pathogen",
"variant", "n", "date"), row.names = c(NA, -10L), class = "data.frame")

我想找到包含前一个 x 个月期间未记录的变量组合的每一行。因此,当我寻找过去 3 个月内未记录的 pathogenvariant 的组合时,我从:

         pathogen variant   n       date
1 MRSA mecA 25 2011-07-01
2 L. pneumophila sg1 14 2011-10-01
3 MRSA mecA 235 2011-11-01
4 L. pneumophila sg1 2 2011-11-01
5 MRSA mecA 64 2011-12-01
6 MRSA mecC 15 2012-01-01
7 MRSA mecA 13 2012-01-01
8 L. pneumophila sg1 6 2012-03-01
9 L. pneumophila sg6 11 2012-04-01
10 MRSA mecA 8 2012-05-01

到:

         pathogen variant   n       date
1 MRSA mecA 25 2011-07-01
2 L. pneumophila sg1 14 2011-10-01
3 MRSA mecA 235 2011-11-01
6 MRSA mecC 15 2012-01-01
8 L. pneumophila sg1 6 2012-03-01
9 L. pneumophila sg6 11 2012-04-01
10 MRSA mecA 8 2012-05-01

到目前为止,我想到的所有解决方案都涉及编写循环。我也在尝试尽可能多地使用 dplyr 进行分析,所以我的问题是:这在 dplyr 中可能吗?如果不可能,R-ish 方法会是什么样子?

最佳答案

我不确定处理精确月份间隔的最佳方法,但为了让您开始,您可以按如下方式计算天数差异(产生与问题中所示相同的输出):

df %>%
group_by(pathogen, variant) %>%
filter(c(TRUE, diff(date) > 90)) # check for difference of 90 days
#Source: local data frame [7 x 4]
#Groups: pathogen, variant
#
# pathogen variant n date
#1 MRSA mecA 25 2011-07-01
#2 L. pneumophila sg1 14 2011-10-01
#3 MRSA mecA 235 2011-11-01
#4 MRSA mecC 15 2012-01-01
#5 L. pneumophila sg1 6 2012-03-01
#6 L. pneumophila sg6 11 2012-04-01
#7 MRSA mecA 8 2012-05-01

关于r - 基于日期范围的不同行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29536874/

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