Elixir - 拆分字符串以便它不会在列表中返回空字符串？

Question

我在正则表达式上拆分字符串。结果数组包含正则表达式匹配的空字符串。我不要那些。例如。，

iex(1)> String.split("Hello world. How are you?", ~r/\W/)
["Hello", "world", "", "How", "are", "you", ""]

如何拆分字符串，使其不会在列表中返回空字符串？

Answer 1

如 the String.split docs 中所述,

Empty strings are only removed from the result if the trim option is set to true (default is false).

因此，您需要在调用 String.split 时将其添加为选项。 :

String.split("Hello world. How are you?", ~r/\W/, trim: true)
["Hello", "world", "How", "are", "you"]