ansible - ansible 中的 JSON 文件列表

Question

有一种方法可以获取 JSON 文件列表，每个文件都代表 Ansible 中 vars.yml 文件中的特定用户。

例子:

-users:

- username: jsmith
  project_role: administrators
  full_name: John Smith
  email: johnsmith@mail.com
- username: pmorrison
  project_role: developer
  full_name: Paul Morrison
  email: paulmorrison@mail.com

例如，我特别想将单个用户设计为单个 json 文件。 John smith 的一个 json 文件包含他的所有信息，一个 paul morrison 的 json 文件包含他的所有信息，依此类推。

谢谢

Answer 1

这可以通过字典中的数据轻松解决。例如

shell> cat user.d/jsmith.yml
jsmith:
  project_role: administrators
  full_name: John Smith
  email: johnsmith@mail.com

shell> cat user.d/pmorrison.yml 
pmorrison:
  project_role: developer
  full_name: Paul Morrison
  email: paulmorrison@mail.com

剧本

shell> cat pb.yml 
- hosts: localhost
  tasks:
    - include_vars:
        dir: user.d
        name: users
    - debug:
        var: users

给

    "users": {
        "jsmith": {
            "email": "johnsmith@mail.com",
            "full_name": "John Smith",
            "project_role": "administrators"
        },
        "pmorrison": {
            "email": "paulmorrison@mail.com",
            "full_name": "Paul Morrison",
            "project_role": "developer"
        }
    }

如果需要，可以创建列表。例如

    - set_fact:
        users_list: "{{ users_list|d([]) +
                        [{'username': item.0}|combine(item.1)] }}"
      with_together:
        - "{{ users.keys()|list }}"
        - "{{ users.values()|list }}"
    - debug:
        var: users_list

给

    "users_list": [
        {
            "email": "johnsmith@mail.com",
            "full_name": "John Smith",
            "project_role": "administrators",
            "username": "jsmith"
        },
        {
            "email": "paulmorrison@mail.com",
            "full_name": "Paul Morrison",
            "project_role": "developer",
            "username": "pmorrison"
        }
    ]