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clickhouse - 日期之间的前 10 名产品

转载 作者:行者123 更新时间:2023-12-04 10:00:12 24 4
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我正在尝试找出创建单个查询的更好方法,该查询将为每个日期生成前 10 个产品的结果。我有一排两列 - PID (int)EventDate (date) ,每次点击一行。

您能否建议我如何通过点击日期范围内的前 10 名产品来获得结果?我一直在理解必须如何构造子查询。我只能按日期获得分组的部分,但随后我的思绪就停留在 count() 和聚合问题上。

这是我对单个日期的查询,但我想查询一个日期范围。当然,我可以通过生成事件日期来进行子查询,但想弄清楚如何更优雅地进行。

SELECT TOP 10 COUNT() as count, PID
FROM view_product
WHERE EventDate = toDate('2020-05-11')
GROUP BY PID
ORDER BY count DESC

预期的输出是这样的:

PID Count Date
1 123 2020-02-04
21 101 2020-02-04
1332 99 2020-02-04
11 51 2020-02-04
634 49 2020-02-04
1332 43 2020-02-04
1 24 2020-02-04
21 23 2020-02-04
1332 6 2020-02-04
11 3 2020-02-04

1 266 2020-02-02
21 241 2020-02-02
1332 232 2020-02-02
11 179 2020-02-02
634 163 2020-02-02
1332 159 2020-02-02
1 144 2020-02-02
21 100 2020-02-02
1332 99 2020-02-02
11 74 2020-02-02

最佳答案

需要使用LIMIT BY - 每天需要 10 行的条款:

SELECT
PID,
EventDate,
count() AS Count
FROM view_product
WHERE EventDate >= '2020-05-01' AND EventDate < '2020-06-01'
GROUP BY EventDate, PID
ORDER BY EventDate, Count DESC
LIMIT 10 BY EventDate;

测试示例:

SELECT
PID,
EventDate,
count() AS Count
FROM (
/* emulate test set */
SELECT test_data.1 AS PID, toDate(test_data.2) AS EventDate
FROM (
SELECT arrayJoin([
(1, '2020-02-04'),
(21, '2020-02-04'),
(1332, '2020-02-04'),
(11, '2020-02-04'),
(634, '2020-02-04'),
(1, '2020-02-04'),
(1, '2020-02-04'),
(21, '2020-02-04'),
(1, '2020-02-04'),
(1, '2020-02-02'),
(21, '2020-02-02'),
(11, '2020-02-02'),
(1332, '2020-02-02'),
(1332, '2020-02-02'),
(1332, '2020-02-02'),
(11, '2020-02-02')]) test_data))
GROUP BY EventDate, PID
ORDER BY EventDate, Count DESC
LIMIT 2 BY EventDate;
/* result
┌──PID─┬──EventDate─┬─Count─┐
│ 1332 │ 2020-02-02 │ 3 │
│ 11 │ 2020-02-02 │ 2 │
│ 1 │ 2020-02-04 │ 4 │
│ 21 │ 2020-02-04 │ 2 │
└──────┴────────────┴───────┘
*/

要获得没有计数值的 n-top 项目,请使用 topK -聚合功能:

SELECT 
EventDate,
topK(10)(PID)
FROM (
/* emulate test set */
SELECT test_data.1 AS PID, toDate(test_data.2) AS EventDate
FROM (
SELECT arrayJoin([
(1, '2020-02-04'),
(21, '2020-02-04'),
(1332, '2020-02-04'),
(11, '2020-02-04'),
(634, '2020-02-04'),
(1, '2020-02-04'),
(1, '2020-02-04'),
(21, '2020-02-04'),
(1, '2020-02-04'),
(1, '2020-02-02'),
(21, '2020-02-02'),
(11, '2020-02-02'),
(1332, '2020-02-02'),
(1332, '2020-02-02'),
(1332, '2020-02-02'),
(11, '2020-02-02')]) test_data))
GROUP BY EventDate;
/* result
┌──EventDate─┬─topK(10)(PID)──────┐
│ 2020-02-02 │ [1332,11,1,21] │
│ 2020-02-04 │ [1,21,1332,11,634] │
└────────────┴────────────────────┘
*/

关于clickhouse - 日期之间的前 10 名产品,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61850167/

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