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python - Pygame表面突然反转变量

转载 作者:行者123 更新时间:2023-12-04 09:56:09 26 4
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这个问题在这里已经有了答案:





Why is my collision test always returning 'true' and why is the position of the rectangle of the image always wrong (0, 0)?

(1 个回答)


11 个月前关闭。




我试图制作一个游戏,你砍掉一些树然后卖掉它,但这样做时我设法找到了一个令人心碎的错误——第一棵树会反转所有其他树!我知道这没有意义,但我的意思是我已经将树分类到一个类中,并创建了一个名为 self.tree_property 的变量实例。这决定了这棵树是否被砍伐了。当你砍倒第一棵树时,所有其他树 tree_property设置为 True再次。当你砍倒任何其他树时,第一棵树的 tree_property设置为 True谁能告诉我如何解决它,以及它为什么会发生?
代码如下:

import pygame
import time
pygame.init()
print('Loading game...')
icon = pygame.image.load('C:\Program Files\Foraging Simulator\icon.png')
market = pygame.image.load('C:\Program Files\Foraging Simulator\market.png')
house = pygame.image.load('C:\Program Files\Foraging Simulator\house.png')
pygame.display.set_icon(icon)
market = pygame.transform.scale(market, (100, 100))
house = pygame.transform.scale(house, (100, 100))
root = pygame.display.set_mode((603, 573))
pygame.display.set_caption("Foraging Simulator")
window_is_open = True
white = (255, 255, 255)
black = (0, 0, 0)
width = 10
leaves_width = 30
height = 20
leaves_height = 10
x = 0
tree_trunk_x = 10
y = 0
tree_trunk_y = 10
vel = 5
brown = (150, 75, 0)
green = (58, 95, 11)
grass = (124, 252, 0)
score = 0
chop_wood = 'C:\Program Files\Foraging Simulator\chopping.mp3'
clock = pygame.time.Clock()
time = 0
happiness = 10
def test(string):
print(string)
def reset_trees():
for tree in trees:
tree.tree_property = True
def open_house():
reset_trees()
score = 0
def open_market():
happiness = score / 2
class Tree: # The class for the trees
def __init__(self, tree_x, tree_y):
self.tree_x = tree_x
self.tree_y = tree_y
self.tree_property = True # Creating instance tree_property
self.trunk = None
self.leaves = None
def destroy(self):
self.tree_property = False
def create_tree(self):
if self.tree_property:
trunk_x = self.tree_x + 10
trunk_y = self.tree_y + 10
self.trunk = pygame.draw.rect(root, brown, (trunk_x, trunk_y, width, height))
self.leaves = pygame.draw.rect(root, green, (self.tree_x, self.tree_y, leaves_width, leaves_height))
def redraw(self):
self.create_tree()
trees = []
for x in range(5):
for y in range (5):
trees.append(Tree(x*50, y*50))
root.fill(grass)
destroy_tree = None
countdown = 3
clock.tick(60)
say = True
print('Loading and attributes finsihed! Using mainloop...')
while window_is_open:
if say:
print('Mainloop loaded! Ready to go.')
say = False
time = pygame.time.delay(100)
for event in pygame.event.get():
if event.type == pygame.QUIT:
window_is_open = False
if event.type == pygame.MOUSEBUTTONDOWN:
mouse_x, mouse_y = event.pos
if market.get_rect().collidepoint(mouse_x, mouse_y):
dx = mouse_x - x
dy = mouse_y - y
if abs(dx) <= 50 and abs(dy) <= 50:
open_market()
mouse_x, mouse_y = event.pos
if house.get_rect().collidepoint(mouse_x, mouse_y):
dx = mouse_x - x
dy = mouse_y - y
if abs(dx) <= 50 and abs(dy) <= 50:
open_house()
for tree in trees: # Clicking detection
mouse_x, mouse_y = pygame.mouse.get_pos()
if tree.trunk.collidepoint(mouse_x, mouse_y):
dx = mouse_x - x
dy = mouse_y - y
if abs(dx) <= 50 and abs(dy) <= 50:
countdown = 3
destroy_tree = tree

keys = pygame.key.get_pressed()
if keys[pygame.K_RIGHT]:
x += vel
if keys[pygame.K_LEFT]:
x -= vel
if keys[pygame.K_UP]:
y -= vel
if keys[pygame.K_DOWN]:
y += vel
if destroy_tree != None:
if countdown == 3:
pygame.time.delay(950)
countdown = countdown - 1
pygame.mixer.music.load(chop_wood)
pygame.mixer.music.play()
while pygame.mixer.music.get_busy():
pygame.time.Clock().tick(1)
elif countdown > 0:
pygame.mixer.music.load(chop_wood)
pygame.mixer.music.play()
while pygame.mixer.music.get_busy():
pygame.time.Clock().tick(1)
pygame.time.delay(950)
countdown = countdown - 1
else:
destroy_tree.destroy()
destroy_tree = None
countdown = 3
score = score + 1
font = pygame.font.SysFont('Tahoma', 18, True, False)
count = font.render(str(countdown), True, (0, 0, 0))
screen_score = font.render("Score: " + str(score), True, (0, 0, 0))
rendered_happiness = font.render("Happines: " + str(happiness), True, (0, 0, 0))
root.blit(rendered_happiness, (410, 40))
root.blit(count, (410, 0))
root.blit(screen_score, (410, 20))
rectangle = pygame.draw.rect(root, (0, 0, 0), (x, y, width, 10))
for tree in trees:
tree.redraw()
root.blit(market, (400, 300))
seconds = clock.tick()
pre = time + seconds / 1000
time = int(pre)
root.blit(house, (400, 100))
pygame.display.update()
root.fill(grass)
pygame.quit()





谢谢!

最佳答案

pygame.Surface 对象没有位置。 get_rect() 返回的矩形的位置总是 (0, 0)。
请注意,当表面为 blit 时,您指定了一个位置。 :

root.blit(house, (400, 100))


当您检索碰撞的矩形时,您必须设置相同的位置。您可以将关键字参数值传递给此函数,这些值设置为 pygame.Rect 目的:

house.get_rect(topleft = (400, 100))

例如:

while window_is_open:
# [...]

for event in pygame.event.get():
if event.type == pygame.QUIT:
window_is_open = False

if event.type == pygame.MOUSEBUTTONDOWN:
mouse_x, mouse_y = event.pos
dx = mouse_x - x
dy = mouse_y - y

if market.get_rect(topleft = (400, 300)).collidepoint(mouse_x, mouse_y):
if abs(dx) <= 50 and abs(dy) <= 50:
open_market()

if house.get_rect(topleft = (400, 100)).collidepoint(mouse_x, mouse_y):
if abs(dx) <= 50 and abs(dy) <= 50:
open_house()

for tree in trees:
if tree.trunk.collidepoint(mouse_x, mouse_y):
if abs(dx) <= 50 and abs(dy) <= 50:
countdown = 3
destroy_tree = tree
# [...]

此外,您必须使用 global statement治疗 happiness作为函数中全局命名空间中的变量 open_market :

def open_market():
global happiness
happiness = score / 2

关于python - Pygame表面突然反转变量,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61921518/

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