spring-boot - 如何将 ConstraintViolationException 500 错误转换为 400 错误请求？

Question

如果我使用这样的约束 @NotNull 然后在 Controller 中

public User createUser(
            @Validated
            @RequestBody User user) {}

它提供了一个非常好的 400 异常细节。

但是，如果我像这样使用自己的自定义验证器:

public User createUser(
            @UserConstraint
            @RequestBody User user) {}

它会抛出一个 500 服务器错误，如下所示:

javax.validation.ConstraintViolationException: createUser.user: Error with field: 'test35'
    at org.springframework.validation.beanvalidation.MethodValidationInterceptor.invoke(MethodValidationInterceptor.java:117) ~[spring-context-5.1.10.RELEASE.jar:5.1.10.RELEASE]
    at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:186) ~[spring-aop-5.1.10.RELEASE.jar:5.1.10.RELEASE]
    at org.springframework.security.access.intercept.aopalliance.MethodSecurityInterceptor.invoke(MethodSecurityInterceptor.java:69) ~[spring-security-core-5.1.6.RELEASE.jar:5.1.6.RELEASE]

有没有办法让 400 消息得到响应？

理想情况下，400 消息应该与 Spring 的验证 JSON 相同

{
    "timestamp": "2019-10-30T02:33:15.489+0000",
    "status": 400,
    "error": "Bad Request",
    "errors": [
        {
            "codes": [
                "Size.user.lastName",
                "Size.lastName",
                "Size.java.lang.String",
                "Size"
            ],
            "arguments": [
                {
                    "codes": [
                        "user.lastName",
                        "lastName"
                    ],
                    "arguments": null,
                    "defaultMessage": "lastName",
                    "code": "lastName"
                },
                25,
                1
            ],
            "defaultMessage": "size must be between 1 and 25",
            "objectName": "user",
            "field": "lastName",
            "rejectedValue": "",
            "bindingFailure": false,
            "code": "Size"
        }
    ],
    "message": "Validation failed for object='user'. Error count: 1",
    "path": "/api/v1/users"
}

Answer 1

是的，您可以创建一个 custom error handler然后您也可以在您的回复和状态中添加任何内容。这是更改状态的简单方法:
1.- 简单的更改方法 status当ConstraintViolationException被抛出。

import javax.validation.ConstraintViolationException;

@ControllerAdvice
public class CustomErrorHandler {

    @ExceptionHandler(ConstraintViolationException.class)
    public void handleConstraintViolationException(ConstraintViolationException exception,
            ServletWebRequest webRequest) throws IOException {
        webRequest.getResponse().sendError(HttpStatus.BAD_REQUEST.value(), exception.getMessage());
    }
}    

2.- 在 ConstraintViolationException 时放置响应的自定义方式发生。

@ControllerAdvice
public class CustomErrorHandler {

    @ExceptionHandler(ConstraintViolationException.class)
    public ResponseEntity<CustomError> handleConstraintViolationException(ConstraintViolationException exception) {
        CustomError customError = new CustomError();
        customError.setStatus(HttpStatus.BAD_REQUEST);
        customError.setMessage(exception.getMessage());
        customError.addConstraintErrors(exception.getConstraintViolations());
        return ResponseEntity.badRequest().body(customError);
    }
}