python - 如何在python中只运行一次循环？

Question

我是 python 和编码的新手，我开发了一个小程序来检查谷歌日历中的双重预订。我的问题是，如果我选择检查 6 月 26 日，它将检查 26 和 27。
我认为这是因为我在 range(1) 中做了一个 for i (所以它循环了两次，(0,1))
我如何更改它以使其仅运行一次？
这是代码:

        for i in range(1):

            startStrip = datetime.datetime.strptime(event_start, "%Y-%m-%dT%H:%M:%S")
            endStrip = datetime.datetime.strptime(event_end, "%Y-%m-%dT%H:%M:%S")
            dayOfWeek = startStrip + datetime.timedelta(days=i)
            # les bons formats
            currentStart = str(startStrip + datetime.timedelta(days=i)).replace(" ", "T")
            currentEnd = str(endStrip + datetime.timedelta(days=i)).replace(" ", "T")
            calendarEnd = str(endStrip + datetime.timedelta(days=i + 1)).replace(" ", "T")

            events_result = service.events().list(calendarId='primary', timeMin=currentStart + "-00:00",
                                                  maxResults=30, timeMax=calendarEnd + "-00:00",
                                                  singleEvents=True, orderBy='startTime').execute()
            events = events_result.get('items', [])

            currentEmployees = []
            for event in events:
                currentEmployees.append(event['summary'])

            #for i in range(1):
            #event_done = False
            if employee in currentEmployees:
                event_done = False
                event['summary'] = employee
                #if employee not in currentEmployees:
                    #event_done = True
                #else:
                for event in events:
                   # if employee == event['summary']:
                   if str2datetime(currentStart) <= str2datetime(event['end']['dateTime'].split('+')[0]) and str2datetime(currentEnd) >= str2datetime(event['start']['dateTime'].split('+')[0]):
                    event_done = False
                    print(employee + ' est occupé')
                    break
                   else:
                      event_done = True
                      break

            if employee not in currentEmployees:
                event_done = True

            if event_done:
                option = show_message_box(QMessageBox.Critical,
                                      "Confirmation",
                                      "Voulez-vous bloquer cette plage horraire?"\
                                      "L'employé : \"" + employee + "\" sera marqué comme indisponible en raison de : " + reason, \
                                      "Nom de l'employé: " + employee + "\n" \
                                      "Raison: " + reason + "\n" \
                                      "À partir du : " + currentStart + "\n" \
                                      "À ce jour " + currentEnd + "\n"
                                      )

                if option == QMessageBox.Yes:
                    event_done = True
                else:
                    print("Événement ignoré!")
                    event_done = False
                    break

                if event_done:
                    event = {
                        'summary': employee,
                        'location': location,
                        'description': reason,
                        'start': {
                            'dateTime': currentStart,
                            'timeZone': 'America/New_York',
                        },
                        'end': {
                            'dateTime': currentEnd,
                            'timeZone': 'America/New_York',
                        #},
                        #'attendees': [
                         #   {'email': event_email},
                        #],
                        #'reminders': {
                         #   'useDefault': True,
                        },
                    }
                    register_event(service, event)

            else:
                second_message_box(QMessageBox.Critical,
                                      "ATTENTION!",
                                      "L'inspecteur " + employee + " est déjà occupé à ce moment-là.""\n" \
                                      "Veuillez essayer une autre plage horraire.", QMessageBox.Ok)

Answer 1

你的第一个循环很好，它只会迭代一次
我不知道你的需求逻辑，但我能看到的是你的 calander_end 你是用 +1 做的，这意味着提前一个日期我猜你必须根据你的要求检查和纠正