python - 是否可以在没有迭代的情况下在python中对xml进行数据帧处理？

Question

无需迭代即可在python中将数据框转换为xml？
输入数据框:

    A   B   C   D
    aa  ab  ac  ad
    aaa abb acc add

以 XML 格式输出:

    <A>aa</A>
    <B>ab</B>
    <C>ac</C>
    <D>ad</D>
    <A>aaa</A>
    <B>abb</B>
    <C>acc</C>
    <D>add</D>

Answer 1

给定数据框 x:

>>> import pandas as pd
>>> x = pd.DataFrame([['aa','ab','ac','ad'],['aaa','abb','acc','add']],columns=['A','B','C','D'])
>>> x
     A    B    C    D
0   aa   ab   ac   ad
1  aaa  abb  acc  add

您可以使用此功能。但是，不能保证此处使用的 pandas 和 numpy 函数不会在内部执行任何循环。

>>> import numpy as np
>>> def to_xml(df):
...     
...     #extract columns and repeat them by number of rows
...     cols = df.columns.tolist()*len(df.index)
...     
...     #convert df to numpy and reshape columns to one vector
...     df_numpy = np.array(df)
...     df_numpy = df_numpy.reshape(np.dot(*df_numpy.shape))
...     
...     #convert columns and numpy array to pandas and apply function that formats each row, convert to list
...     listlike = pd.DataFrame([df_numpy,cols]).apply(lambda x: '<{0}>{1}</{0}>'.format(x[1],x[0])).tolist()
...    
...     #return list of rows joined with newline character
...     return '\n'.join(listlike)

输出:

>>> print(to_xml(x))
<A>aa</A>
<B>ab</B>
<C>ac</C>
<D>ad</D>
<A>aaa</A>
<B>abb</B>
<C>acc</C>
<D>add</D>