Django Rest查询集过滤器通过url参数

Question

我需要根据 url 参数过滤 ListAPIView 中的查询集。基本上，应用程序通过调用 API 来列出事件的所有参与者(用户)，例如 /events/:id/attendees/
您可以在下面找到序列化程序、模型、网址和 View 。我还想知道在 Django REST 中进行此类端点实现的任何其他实践

**serializers.py**
class AttendeeSerializer(serializers.ModelSerializer):
    user = UserSerializer()

    class Meta:
        model = Attendee
        fields = ('user', 'status')


**views.py**
class EventAttendeeList(generics.ListAPIView):
    queryset = Attendee.objects.all()
    serializer_class = AttendeeSerializer
    #permission_classes = (permissions.IsAuthenticatedOrReadOnly,)

    def get_queryset(self):
        # It should filter attendees by event_id posted in URL
        return Attendee.objects.all()

**urls.py**

url(r'^events/(?P<pk>[0-9]+)/attendees/$', views.EventAttendeeList.as_view()),


**models.py**
class Event(models.Model):
    name = models.CharField(max_length=500, blank=True)
    attendees = models.ManyToManyField(settings.AUTH_USER_MODEL, through='Attendee', related_name='attendees_event')


class Attendee(models.Model):
    event = models.ForeignKey(Event, related_name="a_event")
    user = models.ForeignKey(settings.AUTH_USER_MODEL, related_name="a_user")
    requested_on = models.DateTimeField(default=timezone.now)

Answer 1

您可以使用 self.kwargs['parameter_name'] 访问 View 中的 url 参数( http://www.django-rest-framework.org/api-guide/filtering#filtering-against-the-url )。所以最简单的解决方案是

def get_queryset(self):
    return Attendee.objects.filter(event=self.kwargs['pk'])