gpt4 book ai didi

Typeorm - 左连接并仅选择关系实体

转载 作者:行者123 更新时间:2023-12-04 09:32:03 26 4
gpt4 key购买 nike

我有命令:

                .leftJoinAndSelect("permission.user", "user")
.where("permission.stream = :stream", {stream: req.params.id})
.getMany();

这给了我这个输出:

[
Permission {
id: 51,
user: User { nick: 'jmat', password: 'jmat', email: '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="761c1b1702361819021e1f18115815191b" rel="noreferrer noopener nofollow">[email protected]</a>' }
}
]

我只想要这样的输出:

[
User { nick: 'jmat', password: 'jmat', email: '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="2b41464a5f6b45445f4342454c05484446" rel="noreferrer noopener nofollow">[email protected]</a>' }
}
]

我尝试在 where 和 getMany 之间的代码中添加这样的行,但它不起作用。也尝试过使用joinAndMap,但也没有解决。

.select(['user'])
.select(['permission.user']

感谢您的帮助

最佳答案

尝试使用 selectgetRawMany 选项

.leftJoinAndSelect("permission.user", "user")
.where("permission.stream = :stream", {stream: req.params.id})
.select("user")
.getRawMany();

关于Typeorm - 左连接并仅选择关系实体,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62795864/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com