R数据表: update join

Question

假设我有两个数据表:

X <- data.table(id = 1:5, L = letters[1:5])

   id L
1:  1 a
2:  2 b
3:  3 c
4:  4 d
5:  5 e

Y <- data.table(id = 3:5, L = c(NA, "g", "h"), N = c(10, NA, 12))

   id  L  N
1:  3 NA 10
2:  4  g NA
3:  5  h 12

是否可以使用数据表内置函数通过 X对 Y和 id进行左外部联接？如果没有，我想构建一个具有以下预期输出的函数(例如 leftOuterJoin):

leftOuterJoin(X, Y, on = "id")

   id  L  N
1:  1  a NA
2:  2  b NA
3:  3 NA 10
4:  4  g NA
5:  5  h 12

我尝试过但没有成功:

X[Y, on = "id"]

   id L i.L  N
1:  3 c  NA 10
2:  4 d   g NA
3:  5 e   h 12

我也尝试过这个，这几乎是我想要的:

setkey(X, id)
setkey(Y, id)
merge(X, Y, all.x = TRUE)

   id L.x L.y  N
1:  1   a  NA NA
2:  2   b  NA NA
3:  3   c  NA 10
4:  4   d   g NA
5:  5   e   h 12

Answer 1

这是一个更新联接:

library(data.table)
X <- data.table(id = 1:5, L = letters[1:5])
Y <- data.table(id = 3:5, L = c(NA, "g", "h"), N = c(10, NA, 12))
X[Y, on=.(id), c("L", "N"):=.(i.L, i.N)][]
#    id  L  N
# 1:  1  a NA
# 2:  2  b NA
# 3:  3 NA 10
# 4:  4  g NA
# 5:  5  h 12

给您想要的结果。
Here我找到了多个列的解决方案:

library(data.table)
X <- data.table(id = 1:5, L = letters[1:5])
Y <- data.table(id = 3:5, L = c(NA, "g", "h"), N = c(10, NA, 12))

X[Y, on=.(id), names(Y)[-1]:=mget(paste0("i.", names(Y)[-1]))]

另一个变体:

n <- names(Y)
X[Y, on=.(id), (n):=mget(paste0("i.", n))]