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sql - Zend 如何创建左连接

转载 作者:行者123 更新时间:2023-12-04 09:28:40 25 4
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如何打开这个左连接查询:

select advertisercontest.*, advertiseraccount.advertiserid, advertiseraccount.companyname
from advertisercontest
left join advertiseraccount on advertiseraccount.loginid = advertisercontest.loginid
where advertisercontest.golive is not NULL;

在 Zend 中加入左连接?

最佳答案

你可以这样做:

    $db = Zend_Db_Table::getDefaultAdapter();

$select = $db->select();
$select->from('advertisercontest', '*')
->joinLeft(
'advertiseraccount',
'advertiseraccount.loginid = advertisercontest.loginid',
array('advertiseraccount.advertiserid', 'advertiseraccount.companyname')
)
->where('advertisercontest.golive is not NULL');;

$result = $db->fetchAll($select);

var_dump($result);

这是 Zend_Db_Select documentation .

关于sql - Zend 如何创建左连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4955497/

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