r - 用|连接char向量。分隔器

Question

我有一个包含char vectrors的数据结构(请参见下文)。它来自json源，有点困惑。

我需要将经/纬线对用|分隔开，将一个大字符串组合/合并为一个大字符串和经/纬度值，以逗号分隔并删除名称。

即“53.193418，-2881248 | 53.1905138631287，-2.89043889005541 |等”。

我试过了

piped.data<-unname(paste(b, sep="|", collapse=","))

到目前为止，我将值与逗号配对并删除了名称。

我只需要将管道添加到各个对中

有任何想法吗？

dput(b)

structure(c("53.193418", "-2.881248", "53.1905138631287", "-2.89043889005541", 
"53.186744", "-2.890165", "53.189836", "-2.893896", "53.1884117", 
"-2.88802", "53.1902965", "-2.8919373", "53.1940384", "-2.8972299", 
"53.1934748", "-2.8814698", "53.1894004", "-2.8886692", "53.1916771", 
"-2.8846099"), .Names = c("location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude", 
"location.coordinate.latitude", "location.coordinate.longitude"
))

Answer 1

我会将您的“b”转换为2列的matrix并粘贴:

apply(matrix(b, ncol = 2, byrow = TRUE), 1, paste, collapse = "|")
#  [1] "53.193418|-2.881248"              "53.1905138631287|-2.89043889005541"
#  [3] "53.186744|-2.890165"              "53.189836|-2.893896"               
#  [5] "53.1884117|-2.88802"              "53.1902965|-2.8919373"             
#  [7] "53.1940384|-2.8972299"            "53.1934748|-2.8814698"             
#  [9] "53.1894004|-2.8886692"            "53.1916771|-2.8846099" 

编辑

我想我读错了你的问题。

如果您要使用的是单个长字符串，请先用逗号分隔，然后再使用竖线，然后将其粘贴两次:

paste(apply(matrix(b, ncol = 2, byrow = TRUE), 1, paste, collapse = ","), 
      collapse = "|")