java - 似乎无法让它发挥作用。无法按照我的意愿获得中位数

Question

我无法得到中位数。我想要单词的中位数。很难从 for 中获取值(value)环形。

public class MedianWord {
    static double medianWordLength(String words) {
        String[] parts = words.split(" ");
        int[] a;
        double median = 0;

        for (int i = 0; i < parts.length; i++) {
            a = new int[parts[i].length()];
            Arrays.sort(a);
            if (a.length % 2 == 0) {
                median = ((double) a[a.length / 2] + (double) a[a.length / 2 - 1]) / 2;
            }
            else
                median = (double) a[a.length / 2];
        }
        return median;
    }
}

Answer 1

循环的每次迭代都会覆盖 a带有新数组的数组。您需要将问题分为两部分 - 首先，迭代 parts数组并将其转换为数组 a的长度，然后找到该数组的中位数:

static double medianWordLength(String words) {
    String[] parts = words.split(" ");
    int[] a = new int[parts.length];
    for (int i = 0; i < parts.length; i++) {
        a[i] = parts[i].length();
    }

    Arrays.sort(a);
    if (a.length % 2 == 0) {
        return ((double) a[a.length / 2] + (double) a[a.length / 2 - 1]) / 2;
    }
    else {
        return a[a.length / 2];
    }
}

边注:
使用流可以(可以说)更优雅地将单词转换为长度排序的数组:

int[] a = Arrays.stream(words.split(" ")).mapToInt(String::length).sorted().toArray();