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ada - 如何获得整数的 10 对数?

转载 作者:行者123 更新时间:2023-12-04 08:52:46 28 4
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我想请用户输入一个整数(N),然后显示他/她输入的整数的 10 对数。我已经成功计算了 10 对数,但不知道如何像下面这样显示它:

Write in an Integer: 455666
455666 / 10 = 45566
45566 / 10 = 4556
4556 / 10 = 455
455 / 10 = 45
45 / 10 = 4
Answer: 10-logarithm of 455666 is 5.
这是我的代码:
with Ada.Text_IO;                    use Ada.Text_IO;
with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Float_Text_IO; use Ada.Float_Text_IO;

procedure Logarithm is
X: Integer;
begin
Put("Write in an Integer: ");
Get(X);
for I in 1..X loop
if 10**I<=X then
Put(I);
end if;
end loop;
end Logarithm;

最佳答案

以下程序将计算满足 Ada 子类型 Positive 的任何值的整数对数给任何 Positive根据。

with Ada.Text_IO;         use Ada.Text_IO;
with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;

procedure Integer_Logarithm is
subtype Base_Range is Integer range 2..Integer'Last;
Count : Natural := 0;
Base : Base_Range;
Num : Positive;
Inpt : Positive;
begin
Put ("Enter the integer logarithmic base: ");
Get (Base);
Put ("Enter the integer: ");
Get (Inpt);
Num := Inpt;
while Num >= Base loop
Put (Num'Image & " /" & Base'Image & " =");
Num := Num / Base;
Put_Line (Num'Image);
Count := Count + 1;
end loop;
Put_Line
("The integer logarithm (base" & Base'image & ") of" & Inpt'Image &
" is" & Count'Image);
end Integer_Logarithm;
使用上面的示例执行时,结果输出为:
Enter the integer logarithmic base: 10
Enter the integer: 455666
455666 / 10 = 45566
45566 / 10 = 4556
4556 / 10 = 455
455 / 10 = 45
45 / 10 = 4
The integer logarithm (base 10) of 455666 is 5
当为基数 2 和值 256 执行时,结果是
Enter the integer logarithmic base: 2
Enter the integer: 256
256 / 2 = 128
128 / 2 = 64
64 / 2 = 32
32 / 2 = 16
16 / 2 = 8
8 / 2 = 4
4 / 2 = 2
2 / 2 = 1
The integer logarithm (base 2) of 256 is 8

关于ada - 如何获得整数的 10 对数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/64018043/

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