python - Plotly:如何自定义 3D 散点图的符号？

Question

在下面的例子中:

import plotly.express as px
df = px.data.iris()
fig = px.scatter_3d(df, x='sepal_length', y='sepal_width', z='petal_width',
                    color='petal_length', symbol='species')
fig.show()

symbol由 'species' 决定用圆形、菱形和正方形表示。当样本量变大并且样本点涂抹图时，这可能不是很清楚。我们如何自定义符号，比如使用圆形、方形和十字(或其他对比形状的组合)？

更新:
我将代码应用于另一个数据集和代码:

fig = px.scatter_3d(df8, x='X', y='Y', z='Z',
                    color='P', symbol='C')

# specify trace names and symbols in a dict
symbols = {'True': 'cross',
           'False':'circle-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

fig.show()

哪里 C有两个值: True或 False .但是它捕获了错误:

---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
<ipython-input-183-ea1e2ec7dd8e> in <module>
     36 # set all symbols in fig
     37 for i, d in enumerate(fig.data):
---> 38     fig.data[i].marker.symbol = symbols[fig.data[i].name]
     39 
     40 fig.show()

KeyError: 'P, True'

更新:
可重现的例子:

{'ID': {0: '672590',
  1: '672120',
  2: '672090',
  3: '672349',
  4: '672453',
  5: '672560',
  6: '672051',
  7: '880505',
  8: '672593',
  9: '880097',
  10: '891458',
  11: '672091',
  12: '672569',
  13: '672603',
  14: '790030',
  15: '672350',
  16: '673480',
  17: 'I00042',
  18: '880297',
  19: '894620'},
 'X': {0: 0.20111215435497176,
  1: 0.21248998904335528,
  2: 0.2086689759935364,
  3: 0.22337836085443835,
  4: 0.17847099434376115,
  5: 0.24827331723865761,
  6: 0.14411891907440183,
  7: 0.20863940038267367,
  8: 0.166299824101773,
  9: 0.20548401328860527,
  10: 0.18007828100726822,
  11: 0.21887731187605308,
  12: 0.1971207940494219,
  13: 0.19247420041228508,
  14: 0.21605657330040987,
  15: 0.15779241902165092,
  16: 0.22536060645732897,
  17: 0.19268784843224268,
  18: 0.2400112771421119,
  19: 0.22548124117213691},
 'Y': {0: 2473.923076923077,
  1: 2031.1538461538462,
  2: 2383.1923076923076,
  3: 1830.7692307692307,
  4: 1780.2307692307693,
  5: 1194.8461538461538,
  6: 1641.0,
  7: 1563.3076923076924,
  8: 1246.2307692307693,
  9: 931.6153846153846,
  10: 1207.076923076923,
  11: 799.6538461538462,
  12: 560.8461538461538,
  13: 1158.076923076923,
  14: 1221.6923076923076,
  15: 3030.076923076923,
  16: 1178.076923076923,
  17: 552.3846153846154,
  18: 1380.3076923076924,
  19: 1027.5384615384614},
 'Z': {0: 385.84615384615387,
  1: 288.46153846153845,
  2: 281.9230769230769,
  3: 273.61538461538464,
  4: 252.0,
  5: 231.69230769230768,
  6: 213.30769230769232,
  7: 203.3846153846154,
  8: 191.07692307692307,
  9: 189.46153846153845,
  10: 181.07692307692307,
  11: 176.76923076923077,
  12: 173.30769230769232,
  13: 169.6153846153846,
  14: 166.15384615384616,
  15: 165.30769230769232,
  16: 160.53846153846155,
  17: 159.84615384615384,
  18: 159.0,
  19: 145.3846153846154},
 'C': {0: True,
  1: True,
  2: True,
  3: True,
  4: True,
  5: True,
  6: True,
  7: True,
  8: True,
  9: True,
  10: True,
  11: False,
  12: False,
  13: True,
  14: True,
  15: True,
  16: True,
  17: False,
  18: True,
  19: True},
 'P': {0: 'P',
  1: 'P',
  2: 'P',
  3: 'P',
  4: 'P',
  5: 'X',
  6: 'P',
  7: 'P',
  8: 'P',
  9: 'P',
  10: 'P',
  11: 'P',
  12: 'P',
  13: 'P',
  14: 'P',
  15: 'P',
  16: 'P',
  17: 'X',
  18: 'P',
  19: 'P'}}

Answer 1

答案:

# specify trace names and symbols in a dict
symbols = {'setosa': 'cross',
           'versicolor':'circle-open',
           'virginica':'diamond-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

细节:
在这种情况下，您可以手动设置任何标记符号，例如:

fig.data[<i>].marker.symbol = <symbol>

哪里 <i>是一个整数索引，指定您要更改的跟踪，以及 <symbol> 3D 分散对象的属性是一个枚举，可以指定为以下枚举值之一:

['circle', 'circle-open', 'square', 'square-open',
'diamond', 'diamond-open', 'cross', 'x']

示例 1 - 单个跟踪:

fig.data[2].marker.symbol = 'circle-open'
fig.show()

plotly 1:

示例 2 - 多个跟踪:
为了使事情更加动态，您可以使用以下方法检索所有跟踪名称:

['setosa', 'versicolor', 'virginica']

然后您可以指定自己的名称和符号字典，并使用以下方法设置所有跟踪的所有符号:

# specify trace names and symbols in a dict
symbols = {'setosa': 'cross',
           'versicolor':'circle-open',
           'virginica':'diamond-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

fig.show()

plotly 2:

完整代码:

import plotly.express as px
df = px.data.iris()
fig = px.scatter_3d(df, x='sepal_length', y='sepal_width', z='petal_width',
                    color='petal_length', symbol='species')
#fig.show()

# specify trace names and symbols in a dict
symbols = {'setosa': 'cross',
           'versicolor':'circle-open',
           'virginica':'diamond-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

fig.show()

编辑:OP 对附录的回答
这里发生的情况是您在 px.scatter3d 中分配颜色和符号。使用 color='P', symbol='C' .这会对现在的跟踪名称产生影响，例如 'name': 'P, True' .这导致以下内容中断:

for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name]

根据您定义的符号字典判断:

# specify trace names and symbols in a dict
symbols = {'True': 'cross',
           'False':'circle-open'}

看起来您只想通过 'name': 'P, True' 的最后一部分来区分您的符号。是 True或 False .您可以通过在 symbols[fig.data[i].name.split(', ')[1]] 中指定来对符号字典进行子集化从而得到:

带有数据示例的完整代码:

import pandas as pd
import plotly.express as px

df8 = pd.DataFrame({'ID': {0: '672590',
  1: '672120',
  2: '672090',
  3: '672349',
  4: '672453',
  5: '672560',
  6: '672051',
  7: '880505',
  8: '672593',
  9: '880097',
  10: '891458',
  11: '672091',
  12: '672569',
  13: '672603',
  14: '790030',
  15: '672350',
  16: '673480',
  17: 'I00042',
  18: '880297',
  19: '894620'},
 'X': {0: 0.20111215435497176,
  1: 0.21248998904335528,
  2: 0.2086689759935364,
  3: 0.22337836085443835,
  4: 0.17847099434376115,
  5: 0.24827331723865761,
  6: 0.14411891907440183,
  7: 0.20863940038267367,
  8: 0.166299824101773,
  9: 0.20548401328860527,
  10: 0.18007828100726822,
  11: 0.21887731187605308,
  12: 0.1971207940494219,
  13: 0.19247420041228508,
  14: 0.21605657330040987,
  15: 0.15779241902165092,
  16: 0.22536060645732897,
  17: 0.19268784843224268,
  18: 0.2400112771421119,
  19: 0.22548124117213691},
 'Y': {0: 2473.923076923077,
  1: 2031.1538461538462,
  2: 2383.1923076923076,
  3: 1830.7692307692307,
  4: 1780.2307692307693,
  5: 1194.8461538461538,
  6: 1641.0,
  7: 1563.3076923076924,
  8: 1246.2307692307693,
  9: 931.6153846153846,
  10: 1207.076923076923,
  11: 799.6538461538462,
  12: 560.8461538461538,
  13: 1158.076923076923,
  14: 1221.6923076923076,
  15: 3030.076923076923,
  16: 1178.076923076923,
  17: 552.3846153846154,
  18: 1380.3076923076924,
  19: 1027.5384615384614},
 'Z': {0: 385.84615384615387,
  1: 288.46153846153845,
  2: 281.9230769230769,
  3: 273.61538461538464,
  4: 252.0,
  5: 231.69230769230768,
  6: 213.30769230769232,
  7: 203.3846153846154,
  8: 191.07692307692307,
  9: 189.46153846153845,
  10: 181.07692307692307,
  11: 176.76923076923077,
  12: 173.30769230769232,
  13: 169.6153846153846,
  14: 166.15384615384616,
  15: 165.30769230769232,
  16: 160.53846153846155,
  17: 159.84615384615384,
  18: 159.0,
  19: 145.3846153846154},
 'C': {0: True,
  1: True,
  2: True,
  3: True,
  4: True,
  5: True,
  6: True,
  7: True,
  8: True,
  9: True,
  10: True,
  11: False,
  12: False,
  13: True,
  14: True,
  15: True,
  16: True,
  17: False,
  18: True,
  19: True},
 'P': {0: 'P',
  1: 'P',
  2: 'P',
  3: 'P',
  4: 'P',
  5: 'X',
  6: 'P',
  7: 'P',
  8: 'P',
  9: 'P',
  10: 'P',
  11: 'P',
  12: 'P',
  13: 'P',
  14: 'P',
  15: 'P',
  16: 'P',
  17: 'X',
  18: 'P',
  19: 'P'}})

fig = px.scatter_3d(df8, x='X', y='Y', z='Z',
                    color='P', symbol='C')

# specify trace names and symbols in a dict
symbols = {'True': 'cross',
           'False':'circle-open'}

# set all symbols in fig
for i, d in enumerate(fig.data):
    fig.data[i].marker.symbol = symbols[fig.data[i].name.split(', ')[1]]

fig.show()