regex - 抓取字符串直到一两个条件

Question

假设我有以下两个字符串:

...some content above
Destination:        Fox - Man (200.170.217.200)
...some content below

和

...some content above
Destination:        Some content goes here and ends
...some content below

正则表达式应该捕获: Fox - Man和 Some content goes here and ends .
除了尾随括号之外，我想获取描述中的所有内容。基本上，它结合了这两个正则表达式:

Destination:\s*(.+\S)    # everything until the end of the line
Destination:\s*([^(]+\S) # everything until the first open parenthetical

我将如何组合这些，以便 exit at (优先？此处示例: https://regex101.com/r/5qUwRW/1

Answer 1

用

Destination:\s*([^(\n]+[^\s(])

见 proof
说明

--------------------------------------------------------------------------------
  Destination:             'Destination:'
--------------------------------------------------------------------------------
  \s*                      whitespace (\n, \r, \t, \f, and " ") (0 or
                           more times (matching the most amount
                           possible))
--------------------------------------------------------------------------------
  (                        group and capture to \1:
--------------------------------------------------------------------------------
    [^(\n]+                  any character except: '(', '\n'
                             (newline) (1 or more times (matching the
                             most amount possible))
--------------------------------------------------------------------------------
    [^\s(]                   any character except: whitespace (\n,
                             \r, \t, \f, and " "), '('
--------------------------------------------------------------------------------
  )                        end of \1