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RegEx - 在特定短语之间提取字符

转载 作者:行者123 更新时间:2023-12-04 08:47:48 25 4
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我只需要从我得到的血液测试文本中提取测量单位,即“K/UL”、“M/UL”、“%”等。在以下文本中:

WBC                            4.27-11.40 k/uL                        3.64 (L)
RBC 3.90-5.03 m/uL 4.30
Hemoglobin 10.6-13.4 g/dL 13.0
Hematocrit 32.2-39.8 % 36.1
MCV 74.4-87.6 fL 84.0
MCH 24.8-29.5 pG 30.2 (H)
MCHC 31.8-34.9 g/dL 36.0 (H)
RDW-CV 12.2-14.4 % 13.2
Platelet Count 150-400 k/uL 175
MPV 9.2-11.4 fL 8.6 (L)
Neut% 28.6-74.5 % 43.1
Abs Neut (ANC) 1.63-7.87 k/uL 1.57 (L)
Lymph% 15.5-57.8 % 43.7
Abs Lymph 0.97-4.28 k/uL 1.59
Mono% 4.2-12.3 % 9.3
Abs Mono 0.19-0.85 k/uL 0.34
Eosin% 0.0-4.7 % 3.6
Abs Eosin 0.00-0.52 k/uL 0.13
Baso% 0.0-0.7 % 0.3
Abs Baso 0.00-0.06 k/uL 0.01
这意味着我需要识别 '-'+number+' '+ 提取单位
我尝试在表达式后面使用否定查找 (?<!-[0-9]?!([0-9]*[.])?[0-9]+ )(\D)+ ,这意味着如果有一个 '-' 字符后跟一个浮点数,则只匹配非数字,但它会产生零匹配。
请注意,我使用的是 SAS(即 Perl RegEx)。

最佳答案

\d+-\d[\d.]*\s*\K\S+
proof
说明
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
- '-'
--------------------------------------------------------------------------------
\d digits (0-9)
--------------------------------------------------------------------------------
[\d.]* any character of: digits (0-9), '.' (0 or
more times (matching the most amount
possible))
--------------------------------------------------------------------------------
\s* whitespace (\n, \r, \t, \f, and " ") (0 or
more times (matching the most amount
possible))
--------------------------------------------------------------------------------
\K match reset operator
--------------------------------------------------------------------------------
\S+ non-whitespace (all but \n, \r, \t, \f,
and " ") (1 or more times (matching the
most amount possible))

关于RegEx - 在特定短语之间提取字符,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/64223299/

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